Mathematics Questions and Answers – Volume of a Cuboid

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This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Volume of a Cuboid”.

1. Volume of a cuboid of length l, breadth b and height h is given by __________
a) l * b * h
b) l3
c) l2
d) π * l * b * h
View Answer

Answer: a
Explanation: Volume of a cuboid of length l, breadth b and height h = l * b * h
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2. Volume of a cube of sides equal to l is given by __________
a) l * b * h
b) l3
c) l2
d) π * l * b * h
View Answer

Answer: b
Explanation: Volume of a cube of sides equal to l is given by l3.

3. Volume of a cuboid is 1176cm3, its length and breadth are 12cm and 7cm respectively. What is the height of the cuboid?
a) 24cm
b) 11cm
c) 14cm
d) 20cm
View Answer

Answer: c
Explanation: We know that the volume of a cuboid = l * b * h
12 * 7 * h = 1176
h = 14cm.
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4. A wall of dimensions 3m * 12cm * 7m is to be made by using bricks of dimesions 25cm * 12cm * 10cm. How much bricks are required to construct the wall?
a) 825
b) 820
c) 850
d) 840
View Answer

Answer: d
Explanation: For wall, length = 3m = 300cm, breadth = 12cm and height = 7m = 700cm
Volume of the wall = 300 * 12 * 700
= 2520000cm3
Volume of bricks = 25 * 12 * 10
= 3000cm3
Number of bricks required = \(\frac{Volume \,of \,the \,wall}{Volume \,of \,one \,brick}\)
= 252000/3000
= 840.

5. What is the cost of digging a pit of cuboidal shape dimensions of which are 5m * 6m * 3m at the rate of ₹35/m3?
a) ₹3000
b) ₹3150
c) ₹3375
d) ₹3225
View Answer

Answer: b
Explanation: Volume of the pit = 5 * 6 * 3
= 90m3
Cost of digging of 1m3 = ₹35
Therefore, cost of digging 90m3 = 90 * 35
= ₹3150.
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6. A village has population of 1500 people and requirement of water per head is 200 litres. Water container providing water has dimensions 15m * 25m * 12m. For how many days would the water in the container last? (1000 litres = 1m3)
a) 10 days
b) 18 days
c) 12 days
d) 15 days
View Answer

Answer: d
Explanation: Requirement of water of village for one day = 1500 * 200
= 300000 litres
= \(\frac{300000}{1000}\) m3
= 300m3
Volume of the water container = 15 * 25 * 12
= 4500m3
Number of days for which the water in the container would last = \(\frac{Volume \,of \,the \,container}{Water \,requirement \,of \,village \,for \,one \,day} = \frac{4500}{300}\)
= 15 days.

7. A water is flowing through the tap at the rate of 50 cm3/s. What is the time requires to fill the container of dimensions 20cm * 10cm * 10cm?
a) 40 seconds
b) 30 seconds
c) 45 seconds
d) 50 seconds
View Answer

Answer: a
Explanation: Volume of the container = 20 * 10 * 10
= 2000cm3
Time required to fill the container = \(\frac{Volume \,of \,container}{Flow \,rate \,of \,water}\)
= 2000/50
= 40 seconds.
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Sanfoundry Global Education & Learning Series – Mathematics – Class 9.

To practice all areas of Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He is Linux Kernel Developer & SAN Architect and is passionate about competency developments in these areas. He lives in Bangalore and delivers focused training sessions to IT professionals in Linux Kernel, Linux Debugging, Linux Device Drivers, Linux Networking, Linux Storage, Advanced C Programming, SAN Storage Technologies, SCSI Internals & Storage Protocols such as iSCSI & Fiber Channel. Stay connected with him @ LinkedIn | Youtube | Instagram | Facebook | Twitter