This set of Class 9 Maths Chapter 13 Multiple Choice Questions & Answers (MCQs) focuses on “Volume of a Cuboid”.

1. Volume of a cuboid of length l, breadth b and height h is given by __________

a) l * b * h

b) l^{3}

c) l^{2}

d) π * l * b * h

View Answer

Explanation: Volume of a cuboid of length l, breadth b and height h = l * b * h

2. Volume of a cube of sides equal to l is given by __________

a) l * b * h

b) l^{3}

c) l^{2}

d) π * l * b * h

View Answer

Explanation: Volume of a cube of sides equal to l is given by l

^{3}.

3. Volume of a cuboid is 1176cm^{3}, its length and breadth are 12cm and 7cm respectively. What is the height of the cuboid?

a) 24cm

b) 11cm

c) 14cm

d) 20cm

View Answer

Explanation: We know that the volume of a cuboid = l * b * h

12 * 7 * h = 1176

h = 14cm.

4. A wall of dimensions 3m * 12cm * 7m is to be made by using bricks of dimesions 25cm * 12cm * 10cm. How much bricks are required to construct the wall?

a) 825

b) 820

c) 850

d) 840

View Answer

Explanation: For wall, length = 3m = 300cm, breadth = 12cm and height = 7m = 700cm

Volume of the wall = 300 * 12 * 700

= 2520000cm

^{3}

Volume of bricks = 25 * 12 * 10

= 3000cm

^{3}

Number of bricks required = \(\frac{Volume \,of \,the \,wall}{Volume \,of \,one \,brick}\)

= 252000/3000

= 840.

5. What is the cost of digging a pit of cuboidal shape dimensions of which are 5m * 6m * 3m at the rate of ₹35/m^{3}?

a) ₹3000

b) ₹3150

c) ₹3375

d) ₹3225

View Answer

Explanation: Volume of the pit = 5 * 6 * 3

= 90m

^{3}

Cost of digging of 1m

^{3}= ₹35

Therefore, cost of digging 90m

^{3}= 90 * 35

= ₹3150.

6. A village has population of 1500 people and requirement of water per head is 200 litres. Water container providing water has dimensions 15m * 25m * 12m. For how many days would the water in the container last? (1000 litres = 1m^{3})

a) 10 days

b) 18 days

c) 12 days

d) 15 days

View Answer

Explanation: Requirement of water of village for one day = 1500 * 200

= 300000 litres

= \(\frac{300000}{1000}\) m

^{3}

= 300m

^{3}

Volume of the water container = 15 * 25 * 12

= 4500m

^{3}

Number of days for which the water in the container would last = \(\frac{Volume \,of \,the \,container}{Water \,requirement \,of \,village \,for \,one \,day} = \frac{4500}{300}\)

= 15 days.

7. A water is flowing through the tap at the rate of 50 cm^{3}/s. What is the time requires to fill the container of dimensions 20cm * 10cm * 10cm?

a) 40 seconds

b) 30 seconds

c) 45 seconds

d) 50 seconds

View Answer

Explanation: Volume of the container = 20 * 10 * 10

= 2000cm

^{3}

Time required to fill the container = \(\frac{Volume \,of \,container}{Flow \,rate \,of \,water}\)

= 2000/50

= 40 seconds.

**Sanfoundry Global Education & Learning Series – Mathematics – Class 9**.

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