# Mathematics Questions and Answers – Volume of a Cuboid

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This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Volume of a Cuboid”.

1. Volume of a cuboid of length l, breadth b and height h is given by __________
a) l * b * h
b) l3
c) l2
d) π * l * b * h

Explanation: Volume of a cuboid of length l, breadth b and height h = l * b * h

2. Volume of a cube of sides equal to l is given by __________
a) l * b * h
b) l3
c) l2
d) π * l * b * h

Explanation: Volume of a cube of sides equal to l is given by l3.

3. Volume of a cuboid is 1176cm3, its length and breadth are 12cm and 7cm respectively. What is the height of the cuboid?
a) 24cm
b) 11cm
c) 14cm
d) 20cm

Explanation: We know that the volume of a cuboid = l * b * h
12 * 7 * h = 1176
h = 14cm.
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4. A wall of dimensions 3m * 12cm * 7m is to be made by using bricks of dimesions 25cm * 12cm * 10cm. How much bricks are required to construct the wall?
a) 825
b) 820
c) 850
d) 840

Explanation: For wall, length = 3m = 300cm, breadth = 12cm and height = 7m = 700cm
Volume of the wall = 300 * 12 * 700
= 2520000cm3
Volume of bricks = 25 * 12 * 10
= 3000cm3
Number of bricks required = $$\frac{Volume \,of \,the \,wall}{Volume \,of \,one \,brick}$$
= 252000/3000
= 840.

5. What is the cost of digging a pit of cuboidal shape dimensions of which are 5m * 6m * 3m at the rate of ₹35/m3?
a) ₹3000
b) ₹3150
c) ₹3375
d) ₹3225

Explanation: Volume of the pit = 5 * 6 * 3
= 90m3
Cost of digging of 1m3 = ₹35
Therefore, cost of digging 90m3 = 90 * 35
= ₹3150.

6. A village has population of 1500 people and requirement of water per head is 200 litres. Water container providing water has dimensions 15m * 25m * 12m. For how many days would the water in the container last? (1000 litres = 1m3)
a) 10 days
b) 18 days
c) 12 days
d) 15 days

Explanation: Requirement of water of village for one day = 1500 * 200
= 300000 litres
= $$\frac{300000}{1000}$$ m3
= 300m3
Volume of the water container = 15 * 25 * 12
= 4500m3
Number of days for which the water in the container would last = $$\frac{Volume \,of \,the \,container}{Water \,requirement \,of \,village \,for \,one \,day} = \frac{4500}{300}$$
= 15 days.

7. A water is flowing through the tap at the rate of 50 cm3/s. What is the time requires to fill the container of dimensions 20cm * 10cm * 10cm?
a) 40 seconds
b) 30 seconds
c) 45 seconds
d) 50 seconds

Explanation: Volume of the container = 20 * 10 * 10
= 2000cm3
Time required to fill the container = $$\frac{Volume \,of \,container}{Flow \,rate \,of \,water}$$
= 2000/50
= 40 seconds.

Sanfoundry Global Education & Learning Series – Mathematics – Class 9.

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