Mathematics Questions and Answers – Coordinates and Quadrants – 1

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This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Coordinates and Quadrants – 1”.

1. Find the coordinates of point A and B as given in the figure.

a) A(4, 6) and B(4, 6)
b) A(-4, 6) and B(4, -6)
c) A(-4, -6) and B(4, 6)
d) A(4, -6) and B(-4, 6)
View Answer

Answer: b
Explanation: Point A is in 2nd quadrant with coordinates (-4, 6) and Point B is in 4th quadrant with coordinates (4, -6).
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2. Identify the quadrant of point Q.

a) I
b) II
c) III
d) IV
View Answer

Answer: c
Explanation: The axes divide the plane into four parts called quadrants which are numbered in anticlockwise direction as I, II, III, IV. The point Q lies in III quadrant with coordinates (-4, -5).

3. The ordinate and abscissa of point A are ______________

a) 2, 3
b) 3, 2
c) 2, 2
d) 3, 3
View Answer

Answer: a
Explanation: The y-coordinate is called as ordinate and x-coordinate of a point is called abscissa. The ordinate and abscissa of point A are 2 and 3 respectively.
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4. What is the sum of abscissas of point A and B?

a) 7
b) 2
c) 9
d) 3
View Answer

Answer: a
Explanation: Coordinates of point A and B are (2, 2) and (6, 4) respectively.
Abscissa of point A = 2
Abscissa of point B = 5
Sum of abscissas of A and B is 7.

5. What is the sum of abscissa and ordinate of point P and point Q?

a) 2
b) 1
c) 0
d) -1
View Answer

Answer: c
Explanation: Coordinates of point P are (3, 4) and that of point Q are (-5, -3).
Abscissa of P = 3
Ordinate of Q = -3
Sum = 3 + (-3) = 0.
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6. What is the sum of y-coordinates of point G and H?

a) 6
b) -6
c) 3
d) -3
View Answer

Answer: b
Explanation: Coordinates of point G and H are (4, -2) and (-2, -4) respectively.
y-coordinate of G = -2
y-coordinate of H = -4
Sum = (-2) + (-4) = -6.

7. What will be the ordinate of P if sum of abscissa of P and abscissa of Q is 9?

a) 2
b) 9
c) 4
d) 3
View Answer

Answer: d
Explanation: Coordinates of point Q = (6, 6).
Abscissa (x-coordinate) of Q = 6
Sum of abscissa of P and abscissa of Q = 9
Abscissa of P = 9 – 6 = 3.
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8. Calculate the length of Line PQ.

a) 10
b) 9
c) 8
d) 7
View Answer

Answer: a
Explanation: Coordinates of P = (-3, 4)
Coordinates of Q = (7, 4)
Length of line PQ = x-coordinate of P + x-coordinate of Q
= 3 + 7 = 10 units.

9. Find the coordinates of a point which is at a distance of 4m to the right of A and 2m above A.

a) (0, 7)
b) (2, 7)
c) (7, 7)
d) (2, 4)
View Answer

Answer: c
Explanation: Coordinates of A = (3, 5)
Abscissa of new point = Abscissa of A + 4 = 3 + 4 = 7
Ordinate of new point = Ordinate of A + 2 = 5 + 2 = 7
Coordinates of new point = (7, 7).
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Sanfoundry Global Education & Learning Series – Mathematics – Class 9.

To practice all areas of Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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