Mathematics Questions and Answers – Zeroes of Polynomial

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This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Zeroes of Polynomial”.

1. If p(x) = 4x2+7x-8, then the value of p(2) is __________
a) 20
b) 18
c) 22
d) 14
View Answer

Answer: c
Explanation: If p(x) is any polynomial, then p(a) means substituting x by a in a polynomial.
Therefore, p(2) means, putting 2 in place of x in 4x2+7x-8.
Hence, p(2) = 4(2)2+7(2)-8 = 4(4) + 14 – 8
= 16 + 14 – 8
= 22.
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2. What is the zero of p(x) = x2+6x+9?
a) -3
b) -6
c) -9
d) -2
View Answer

Answer: a
Explanation: If p(x) is any polynomial, then for “a” to be a zero of the polynomial p(x), p(a) = 0.
Therefore, equating p(x) with 0, we get x2+6x+9=0
(x+3)2 = 0
x+3 = 0
x = -3
Hence, -3 is the zero of the polynomial x2+6x+9 because p(-3) = 0.

3. \(\frac{(5x^3 + 2x^2 + x)}{x}\) = __________
a) 5x3 + 2x2 + 1
b) 5x4 + 2x3 + x
c) 5x2 + 2x2 + x
d) 5x2 + 2x + 1
View Answer

Answer: d
Explanation: \(\frac{(5x^3 + 2x^2 + x)}{x} = \frac{5x^3}{x} + \frac{2x^2}{x} + \frac{x}{x}\)
= 5x2 + 2x + 1.
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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He is Linux Kernel Developer & SAN Architect and is passionate about competency developments in these areas. He lives in Bangalore and delivers focused training sessions to IT professionals in Linux Kernel, Linux Debugging, Linux Device Drivers, Linux Networking, Linux Storage, Advanced C Programming, SAN Storage Technologies, SCSI Internals & Storage Protocols such as iSCSI & Fiber Channel. Stay connected with him @ LinkedIn | Youtube | Instagram | Facebook | Twitter