Class 9 Maths MCQ – Linear Equations Solutions

This set of Class 9 Maths Chapter 4 Multiple Choice Questions & Answers (MCQs) focuses on “Linear Equations Solutions”.

1. Which of the following is the solution for 2x+4y=12?
a) x=2, y=2
b) x=1, y=0
c) x=3, y=1
d) x=-1, y=4
View Answer

Answer: a
Explanation: To find the solution of given equation, put the respective values of x and y in the given equation. If it satisfies the equation, it is the solution of given equation.
Let’s check the values given in option a, which are x=2,y=2.
2(2) + 4(2) = 4 + 8 = 12
Which satisfies the equation 2x+4y=12
Hence, it is the solution of the given equation.

2. What are the number of solutions of linear equation 2x+4y=12?
a) One
b) Two
c) Three
d) Infinite
View Answer

Answer: d
Explanation: To find the solution, we can select arbitrary value of either x or y and we will get the appropriate value of the other variable.
Suppose we take value of x=0, then we get 2(0) + 4y=12
Therefore, y=4
Now, for x = 1, we get 2(1) + 4y = 12
Therefore, y = 10/4
y = 2.5
Likewise, we can get infinite solutions by taking arbitrary values of either x or y.

Sanfoundry Global Education & Learning Series – Mathematics – Class 9.


To practice all chapters and topics of class 9 Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.