This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Graph of a Linear Equations in Two Variables”.

1. Which of the following represents the graph for equation x+y=3?

a)

b)

c)

d)

View Answer

Answer: b

Explanation: To locate the points of the equations on graph, let’s take arbitrary value of x and y equal to zero.

By taking x = 0, we get 0 + y = 3

Therefore, y = 3

First point is (0, 3)

Now by taking y = 0, we get x + 0 = 3

Therefore x = 3

Hence, second point is (3, 0)

Now that we have two points, we can generate a line by locating two points (0, 3) and (3, 0)

Considering this,

above graphis correct as the line passes through two points (0, 3) and (3, 0).

Explanation: To locate the points of the equations on graph, let’s take arbitrary value of x and y equal to zero.

By taking x = 0, we get 0 + y = 3

Therefore, y = 3

First point is (0, 3)

Now by taking y = 0, we get x + 0 = 3

Therefore x = 3

Hence, second point is (3, 0)

Now that we have two points, we can generate a line by locating two points (0, 3) and (3, 0)

Considering this,

above graphis correct as the line passes through two points (0, 3) and (3, 0).

2. What are the number of solutions of set of linear equations x+2y=6 and 3x+6y=16?

a) One

b) Two

c) Zero

d) Infinite

View Answer

Answer: c

Explanation: First equation is x+2y=6 and second equation is 3x+6y=16.

By multiplying the first equation by 3, we get 3x+6y=18, but according to the second equation, 3x+6y=16, which is impossible. Hence, given set of equations has no equation.

Explanation: First equation is x+2y=6 and second equation is 3x+6y=16.

By multiplying the first equation by 3, we get 3x+6y=18, but according to the second equation, 3x+6y=16, which is impossible. Hence, given set of equations has no equation.

**Sanfoundry Global Education & Learning Series – Mathematics – Class 9**.

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