This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Graph of a Linear Equations in Two Variables”.

1. Which of the following represents the graph for equation x+y=3?

a)

b)

c)

d)

View Answer

Answer: b

Explanation: To locate the points of the equations on graph, let’s take arbitrary value of x and y equal to zero.

By taking x = 0, we get 0 + y = 3

Therefore, y = 3

First point is (0, 3)

Now by taking y = 0, we get x + 0 = 3

Therefore x = 3

Hence, second point is (3, 0)

Now that we have two points, we can generate a line by locating two points (0, 3) and (3, 0)

Considering this,

above graphis correct as the line passes through two points (0, 3) and (3, 0).

Explanation: To locate the points of the equations on graph, let’s take arbitrary value of x and y equal to zero.

By taking x = 0, we get 0 + y = 3

Therefore, y = 3

First point is (0, 3)

Now by taking y = 0, we get x + 0 = 3

Therefore x = 3

Hence, second point is (3, 0)

Now that we have two points, we can generate a line by locating two points (0, 3) and (3, 0)

Considering this,

above graphis correct as the line passes through two points (0, 3) and (3, 0).

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2. What are the number of solutions of set of linear equations x+2y=6 and 3x+6y=16?

a) One

b) Two

c) Zero

d) Infinite

View Answer

Answer: c

Explanation: First equation is x+2y=6 and second equation is 3x+6y=16.

By multiplying the first equation by 3, we get 3x+6y=18, but according to the second equation, 3x+6y=16, which is impossible. Hence, given set of equations has no equation.

Explanation: First equation is x+2y=6 and second equation is 3x+6y=16.

By multiplying the first equation by 3, we get 3x+6y=18, but according to the second equation, 3x+6y=16, which is impossible. Hence, given set of equations has no equation.

**Sanfoundry Global Education & Learning Series – Mathematics – Class 9**.

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