This set of Class 9 Maths Chapter 15 Multiple Choice Questions & Answers (MCQs) focuses on “Probability”. These MCQs are created based on the latest CBSE syllabus and the NCERT curriculum, offering valuable assistance for exam preparation.

1. Two coins were tossed 200 times and the following results were obtained.

Two heads: 55 One head and one tail: 105 Two tails: 40

What is the probability of event of obtaining minimum one head?

a) 0.5

b) 0.8

c) 0.55

d) 0.16

View Answer

Explanation: Number of events of obtaining minimum one head = 55 + 105

= 160

Hence, P (E) = probability of event of obtaining minimum on head

= \(\frac{Number \,of \,events \,of \,obtaining \,minimum \,one \,head}{Number \,of \,total \,trials}\)

= \(\frac{160}{200}\)

= 0.8.

2. A dice was thrown 500 times. Frequencies for the outcomes 1, 2, 3, 4, 5, and 6 are given in the table.

Outcome | 1 | 2 | 3 | 4 | 5 | 6 |
---|---|---|---|---|---|---|

Frequency | 78 | 80 | 93 | 79 | 91 | 79 |

What is the probability of getting ‘4’ as outcome?

a) 0.16

b) 0.158

c) 0.156

d) 0.131

View Answer

Explanation: We can see from the table that we get ‘4’ 79 times out of 500 trials.

Therefore, probability of getting ‘4’ as outcome = \(\frac{Event \,of \,occurence \,of \,getting \,’4′}{Total \,number \,of \,trials}\)

= \(\frac{79}{500}\)

= 0.158.

3. Marks obtained by a student in a test is shown in the table below.

Test no. | 1 | 2 | 3 | 4 | 5 |
---|---|---|---|---|---|

Marks | 81 | 87 | 76 | 70 | 90 |

What is the probability that the student has scored more than 80?

a) 0.6

b) 0.8

c) 0.4

d) 0.5

View Answer

Explanation: It can be seen that the student have scored 3 out of 5 times more than 80 marks.

Therefore, probability that the student has scored more than 80 = \(\frac{number \,of \,occurrence \,of \,event}{Total \,number \,of \,trials}\)

= \(\frac{3}{5}\)

= 0.6.

4. 1000 families with 2 children were studied and the following data was collected.

Number of boys in the family | 0 | 1 | 2 |
---|---|---|---|

Number of families | 270 | 415 | 315 |

What is the probability that the family has at least one boy?

a) 0.415

b) 0.270

c) 0.73

d) 0.315

View Answer

Explanation: In this case, having at least one boy means one boy or two boys.

Hence, number of families having at least one boy = 415 + 315 = 730

Therefore, the probability that the family has at least one boy = \(\frac{number \,of \,families \,having \,at \,least \,one \,boy }{Total \,number \,of \,families} = \frac{730}{1000}\)

= 0.73.

5. 1500 drivers were selected for a study to find a relationship between age and accidents. The data is shown in the table below.

Age of drivers(in years) | Number of accidents | ||
---|---|---|---|

0 | 1 | More than 1 | |

18-35 | 285 | 325 | 90 |

35-50 | 145 | 277 | 78 |

Above 50 | 123 | 118 | 59 |

What is the probability of being 18-35 years of age and having more than 1 accidents?

a) 0.06

b) 0.6

c) 0.08

d) 0.1

View Answer

Explanation: We can see that total number of events of being 18-35 years of age and having more than 1 accidents = 90

Total number of events = 1500

Hence, probability of being 18-35 years of age and having more than 1 accidents = \(\frac{90}{1500}\)

= 0.06.

6. 1500 drivers were selected for a study to find a relationship between age and accidents. The data is shown in the table below.

Age of drivers(in years) | Number of accidents | ||
---|---|---|---|

0 | 1 | More than 1 | |

18-35 | 285 | 325 | 90 |

35-50 | 145 | 277 | 78 |

Above 50 | 123 | 118 | 59 |

What is the probability of being elder than 35 years of age and having at least one accident?

a) 0.41

b) 0.25

c) 0.354

d) 0.333

View Answer

Explanation: We can see that total number of events of being elder than 35 years of age and having at least 1 accident = 277 + 78 + 118 + 59

= 532

Total number of events = 1500

Hence, probability of being 18-29 years of age and having more than 1 accidents = \(\frac{532}{1500}\)

= 0.354.

7. 1500 drivers were selected for a study to find a relationship between age and accidents. The data is shown in the table below.

Age of drivers(in years) | Number of accidents | ||
---|---|---|---|

0 | 1 | More than 1 | |

18-35 | 285 | 325 | 90 |

35-50 | 145 | 277 | 78 |

Above 50 | 123 | 118 | 59 |

What is the probability of being 35-50 years of age and having more no accidents?

a) 0.29

b) 0.35

c) 0.09

d) 0.08

View Answer

Explanation: We can see that total number of events of being 35-50 years of age and having more than 1 accidents = 145

Total number of events = 1500

Hence, probability of being 18-29 years of age and having more than 1 accidents = \(\frac{145}{1500}\)

= 0.29.

To practice all chapters and topics of class 9 Mathematics, __ here is complete set of 1000+ Multiple Choice Questions and Answers__.

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