Electronic Devices and Circuits Questions and Answers – Sinusoidal Steady State Analysis

This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Sinusoidal Steady State Analysis”.

1. i(t) = ?
Find i(t) in the given circuit diagram
a) 20 cos (300t + 68.2) A
b) 20 cos(300t – 68.2) A
c) 2.48 cos(300t + 68.2) A
d) 2.48 cos(300t – 68.2) A
View Answer

Answer: d
Explanation: i(t) ia 2.48 cos(300t – 68.2) A in the given diagram

2. Vc(t) = ?
Find Vc(t) in the given circuit diagram
a) 0.89 cos (1000t – 63.43) V
b) 0.89 cos (1000t + 63.43) V
c) 0.45 cos (1000t + 26.57) V
d) 0.45 cos (1000t – 26.57) V
View Answer

Answer: a
Explanation: Vc(t) is 0.89 cos (1000t – 63.43) V in the given diagram

3. Vc(t) = ?
Find Vc(t) is equal to in the given diagram
a) 2.25 cos (5t + 150) V
b) 2.25 cos (5t – 150) V
c) 2.25 cos (5t + 140.71) V
d) 2.25 cos (5t – 140.71) V
View Answer

Answer: d
Explanation: Vc(t) is 2.25 cos (5t – 140.71) V in the given diagram
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4. i(t) = ?
Find i(t) is equal to in the given diagram
a) 2 sin (2t 5.77) A
b) cos (2t 84.23) A
c) 2 sin (2t 5.77) A
d) cos (2t 84.23) A
View Answer

Answer: b
Explanation: i(t) is cos (2t 84.23) A in the given diagram

5. In the bridge shown, Z1 = 300 ohm, Z2 = 400 – j300 ohm, Z3 = 200 + j100 ohm. The Z4 at balance is
The Z4 at balance is 400 – j300 ohm in bridge Z1 = 300 ohm, Z2 = 400 – j300 ohm
a) 400 + j300 ohm
b) 400 – j300 ohm
c) j100 ohm
d) -j900 ohm
View Answer

Answer: b
Explanation: Use Z1 x Z4 = Z2 x Z3.

6. i1(t) = ?
Find i1(t) is equal to in the given diagram
a) 2.36 cos (4t 41.07) A
b) 2.36 cos (4t 41.07) A
c) 1.37 cos (4t 41.07) A
d) 2.36 cos (4t 41.07) A
View Answer

Answer: c
Explanation:i1(t) is 1.37 cos (4t 41.07) A in the given diagram

7. i2(t) = ?
Find i1(t) is equal to in the given diagram
a) 2.04 sin (4t 92.13) A
b) 2.04 sin (4t 2.13) A
c) 2.04 cos (4t 2.13) A
d) 2.04 cos (4t 92.13) A
View Answer

Answer: b
Explanation: i2(t) is 2.04 sin (4t 2.13) A in the given diagram
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8. In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66 sin (1000t) V, i(t) = 2.3sin (1000t + 68.3) 3 A. The nature of the elements would be
a) R C
b) L C
c) R L
d) R R
View Answer

Answer: a
Explanation: RC circuit causes a positive shift in the circuit.

9. P = 269 W, Q = 150 VAR (capacitive). The power in the complex form is
a) 150 – j269 VA
b) 150 + j269 VA
c) 269 – j150 VA
d) 269 + j150 VA
View Answer

Answer: c
Explanation: S = P – jQ.
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10. Q = 2000 VAR, pf = 0.9 (leading). The power in complex form is
a) 4129.8 j2000 VA
b) 2000 j4129.8 VA
c) 2000 j41.29.8 VA
d) 4129.8 j2000 VA
View Answer

Answer: d
Explanation: Use cos T = 0.9 or T = 25.84 degrees.
Q = S sin T or S = 4588.6 VA
p = S cos T or P = 0.9 X 4588.6 4129.8 VA.

Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.

To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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