This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Sinusoidal Steady State Analysis”.
1. i(t) = ?
a) 20 cos (300t + 68.2) A
b) 20 cos(300t – 68.2) A
c) 2.48 cos(300t + 68.2) A
d) 2.48 cos(300t – 68.2) A
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Explanation:
2. Vc(t) = ?
a) 0.89 cos (1000t – 63.43) V
b) 0.89 cos (1000t + 63.43) V
c) 0.45 cos (1000t + 26.57) V
d) 0.45 cos (1000t – 26.57) V
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Explanation:
3. Vc(t) = ?
a) 2.25 cos (5t + 150) V
b) 2.25 cos (5t – 150) V
c) 2.25 cos (5t + 140.71) V
d) 2.25 cos (5t – 140.71) V
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Explanation:
4. i(t) = ?
a) 2 sin (2t 5.77) A
b) cos (2t 84.23) A
c) 2 sin (2t 5.77) A
d) cos (2t 84.23) A
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Explanation:
5. In the bridge shown, Z1 = 300 ohm, Z2 = 400 – j300 ohm, Z3 = 200 + j100 ohm. The Z4 at balance is
a) 400 + j300 ohm
b) 400 – j300 ohm
c) j100 ohm
d) -j900 ohm
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Explanation: Use Z1 x Z4 = Z2 x Z3.
6. i1(t) = ?
a) 2.36 cos (4t 41.07) A
b) 2.36 cos (4t 41.07) A
c) 1.37 cos (4t 41.07) A
d) 2.36 cos (4t 41.07) A
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Explanation:
7. i2(t) = ?
a) 2.04 sin (4t 92.13) A
b) 2.04 sin (4t 2.13) A
c) 2.04 cos (4t 2.13) A
d) 2.04 cos (4t 92.13) A
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Explanation:
8. In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66 sin (1000t) V, i(t) = 2.3sin (1000t + 68.3) 3 A. The nature of the elements would be
a) R C
b) L C
c) R L
d) R R
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Explanation: RC circuit causes a positive shift in the circuit.
9. P = 269 W, Q = 150 VAR (capacitive). The power in the complex form is
a) 150 – j269 VA
b) 150 + j269 VA
c) 269 – j150 VA
d) 269 + j150 VA
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Explanation: S = P – jQ.
10. Q = 2000 VAR, pf = 0.9 (leading). The power in complex form is
a) 4129.8 j2000 VA
b) 2000 j4129.8 VA
c) 2000 j41.29.8 VA
d) 4129.8 j2000 VA
View Answer
Explanation: Use cos T = 0.9 or T = 25.84 degrees.
Q = S sin T or S = 4588.6 VA
p = S cos T or P = 0.9 X 4588.6 4129.8 VA.
Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.
To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.
