Electronic Devices and Circuits Questions and Answers – The JFET Volt-Ampere Characteristics

This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “The JFET Volt-Ampere Characteristics”.

1. For low value of VDS, the JFET behaves like a __________
a) Voltage Variable Resistor
b) Constant Voltage Device
c) Amplifier
d) Switch
View Answer

Answer: a
Explanation: When VDS voltage is very less, there will not be much current flow, since as the VDS changes, the current value changes very little. Hence we can say that FET works as a voltage controlled Resistor.

2. If a JFET with length L=10µm, a=2µm, W=8µm, Vp=-4V.What is the value of rds at Vgs = 0V?
a) 2KΩ
b) 5.2KΩ
c) 10KΩ
d) 9.8KΩ
View Answer

Answer: d
Explanation: rds=L/(2aqND µnW) = Nd = 2V/qa2=1.33×1021 atoms/m3
µn=0.15m2/v-sec
On substituting the values, we get rds=9.8KΩ.

3. A JFET has ID=10mA, IDSS=1A, Vp=-1v, what is the value of Vgs?
a) -0.9V
b) 1V
c) -1V
d) 0.5V
View Answer

Answer: a
Explanation:The value of Vgs is -0.9V for JFET has ID=10mA, IDSS=1A, Vp=-1v
advertisement
advertisement

4. Where does the transfer curve lie for a p- channel FET?
a) First quadrant
b) Second quadrant
c) Third quadrant
d) Fourth quadrant
View Answer

Answer: a
Explanation: For a P- channel FET, since the pinch off lies on right side of the origin, the current Id will increase from VP and rise to its left until it reaches IDSS. Usually IDSS lies on positive Y axis, therefore we can say transfer curve for the p-channel FET lies on first quadrant.

5. For an n-channel FET, the current v at Vgs=-2V and Vds=5V was found to be 2mA, what will be the value of ID at Vgs=0V and Vds=5V?
a) 0A
b) 2mA
c) Lesser than 0A
d) Greater than 2mA
View Answer

Answer: d
Explanation: We know that for a n channel FET, the current will flow only if Vgs is greater than Vp, since in this case current is flowing, which indicates Vgs is greater than pinch off. But as Vgs increases the flow of current also increases, hence it will be greater than 2mA.
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

6. For a p-channel FET, the current ID at Vgs = 2V and Vds = 5V and Vgs = 3V was found to be 2mA, what will be the value of ID at Vgs = 0V and Vds = 5V?
a) 0A
b) 2mA
c) Lesser than 0A
d) Greater than 2mA
View Answer

Answer: a
Explanation: We know that for a p channel FET, the current will flow only if Vgs is lesser than Vgs, but here pinch off voltage is 3V, when Vgs=5V which is greater than pinch off voltage the channel will be destroyed resulting in no conventional current flow.

7. A FET is biased at ID = IDSS/4, at this point the value of trans conductance is __________________ (ID=10mA, Vp=-5V).
a) 1mA/V
b) 2mA/V
c) 3mA/V
d) 4mA/V
View Answer

Answer: b
Explanation: The value of trans conductance is 2mA/V
advertisement

8. What is the value of resultant gm if two non identical FETs are connected in parallel?
a) (µ1 rd1 + µ2 rd2)/ (rd1+rd2)
b) (µ1 rd2 + µ2 rd1)/ (rd1+rd2)
c) 0
d) µ1 rd1+ µ2 rd2
View Answer

Answer: b
Explanation: we know that µ=gm rd
But gm’=gm1+gm2
And rd’=rd1 ×rd2/rd1+ rd2
From the above two equations, gm’=(µ1 rd2 + µ2 rd1)/ (rd1+rd2).

9. What will be the value of rd, if two identical FETs are connected in parallel?
a) Doubles
b) Reduces to half
c) 0
d) Infinite
View Answer

Answer: b
Explanation: rd’=rd1 ×/rd1+ rd2
If rd1=rd1=rd => then rd’=rd2/2rd =rd/2.
advertisement

10. What will be the value of trans conductance if two Identical FETs are connected in parallel?
a) Doubles
b) Reduces to half
c) 0
d) Infinite
View Answer

Answer: a
Explanation: gm’=IDS/Vgs at VDS=0V, if two FET are identical then,
gm1=gm2=gm
But gm’=gm1+gm2
Therefore gm’=gm+gm=2gm.

Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.

To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.