# Electronic Devices and Circuits Questions and Answers – Two Port Network

This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Two Port Network”.

1. [T] = ?

a) $$\begin{bmatrix} 0.35 & -1\\ 2 & -3.33 \end{bmatrix}$$
b) $$\begin{bmatrix} 0.35 & -1\\ -2 & -3.33 \end{bmatrix}$$
c) $$\begin{bmatrix} 2 & 3.33\\ 0.35 & 1 \end{bmatrix}$$
d) $$\begin{bmatrix} 0.35 & 1\\ 2 & 3.33 \end{bmatrix}$$
View Answer

Answer: d
Explanation:

2. [h] = ?

a) $$\begin{bmatrix} 4 & \frac{3}{2}\\ -2 & \frac{1}{2} \end{bmatrix}$$
b) $$\begin{bmatrix} -2 & \frac{1}{2}\\ 4 & \frac{3}{2} \end{bmatrix}$$
c) $$\begin{bmatrix} 4 & -\frac{3}{2}\\ 2 & \frac{1}{2} \end{bmatrix}$$
d) $$\begin{bmatrix} 2 & \frac{1}{2}\\ 4 & -\frac{3}{2} \end{bmatrix}$$
View Answer

Answer: a
Explanation: V2 = 2I2 + 4I1 and
I1 = 0.5I2 + 0.5(V1 – 2V2) => V1 = 4I1 + 1.5V2.

3. [y] = ?

a) $$\begin{bmatrix} Y_a + Y_{ab} & -Y_{ab}\\ -Y_{ab} & Y_b + Y_{ab} \end{bmatrix}$$
b) $$\begin{bmatrix} Y_a – Y_{ab} & Y_{ab}\\ Y_{ab} & Y_b – Y_{ab} \end{bmatrix}$$
c) $$\begin{bmatrix} Y_{ab} – Y_a & Y_{ab}\\ Y_{ab} & Y_{ab} -Y_a \end{bmatrix}$$
d) $$\begin{bmatrix} Y_a – Y_{ab} & -Y_{ab}\\ -Y_{ab} & Y_b – Y_{ab} \end{bmatrix}$$
View Answer

Answer: a
Explanation: I1 = V1(Ya + Yab) – V2(Yab) and I2 = -V1(Yab) + V2(Yb + Yab).
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4.The [y] parameter of a two port network is given by

a) $$\begin{bmatrix} 6 & 4\\ 2 & 3 \end{bmatrix}$$S
b) $$\begin{bmatrix} 6 & 2\\ 0 & 3 \end{bmatrix}$$S
c) $$\begin{bmatrix} 5 & 4\\ 2 & 2 \end{bmatrix}$$S
d) $$\begin{bmatrix} 4 & 4\\ 2 & 1 \end{bmatrix}$$S
View Answer

Answer: b
Explanation: The new parameter will be the sum of the previous network and the resistor parameter.

5. The [y] parameter for a 2-port network and the network itself are given below.

The value of Vo/vs is _______
a) 3/32
b) 1/16
c) 2/33
d) 1/17
View Answer

Answer: a
Explanation:
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6. [y] = ?

a) $$\begin{bmatrix} \frac{19}{10} & \frac{-9}{10}\\ -\frac{9}{10} & \frac{31}{10} \end{bmatrix}$$
b) $$\begin{bmatrix} \frac{19}{10} & \frac{-7}{10}\\ -\frac{7}{10} & \frac{31}{10} \end{bmatrix}$$
c) $$\begin{bmatrix} \frac{19}{10} & \frac{9}{10}\\ \frac{9}{10} & \frac{31}{10} \end{bmatrix}$$
d) $$\begin{bmatrix} \frac{19}{10} & \frac{7}{10}\\ \frac{7}{10} & \frac{31}{10} \end{bmatrix}$$
View Answer

Answer: b
Explanation:

7. A 2-port resistive network satisfy the condition A = D = 3/2B = 4/3C. The z11 of the network is
a) 4/3
b) 3/4
c) 2/3
d) 3/2
View Answer

Answer: a
Explanation: z11 = A/C = 4/3.
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8. A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters are

The Thevenin equivalent circuit presented to the 25 ohm resistor is
a) 80 V, 2.8 ohm
b) 160 V, 6.8 ohm
c) 100 V, 2.4 ohm
d) 120 V, 6.4 ohm
View Answer

Answer: b
Explanation: 100 = 25I1 + 2I2, V2 = 40I1 + 10I2
Also V2 = 160I1 + 6.8I2
using above equations we get, Vth = 160 V and Rth = 6.8 ohm.

9. Find V1 and V2.

a) -68.6 V, 114.3 V
b) 68.6 V, -114.3 V
c) 114.3 V, -68.6 V
d) -114.3 V, 68.6 V
View Answer

Answer: b
Explanation: 800 = 10V1 – V2 and 3V2 = 5V1 = 0.
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Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.

To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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