This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Two Port Network”.
Explanation: V2 = 2I2 + 4I1 and
I1 = 0.5I2 + 0.5(V1 – 2V2) => V1 = 4I1 + 1.5V2.
Explanation: I1 = V1(Ya + Yab) – V2(Yab) and I2 = -V1(Yab) + V2(Yb + Yab).
Explanation: The new parameter will be the sum of the previous network and the resistor parameter.
7. A 2-port resistive network satisfy the condition A = D = 3/2B = 4/3C. The z11 of the network is
Explanation: z11 = A/C = 4/3.
8. A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters are
The Thevenin equivalent circuit presented to the 25 ohm resistor is
a) 80 V, 2.8 ohm
b) 160 V, 6.8 ohm
c) 100 V, 2.4 ohm
d) 120 V, 6.4 ohm
Explanation: 100 = 25I1 + 2I2, V2 = 40I1 + 10I2
Also V2 = 160I1 + 6.8I2
using above equations we get, Vth = 160 V and Rth = 6.8 ohm.
Explanation: 800 = 10V1 – V2 and 3V2 = 5V1 = 0.
Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.
To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.