This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Two Port Network”.

Explanation: V2 = 2I2 + 4I1 and

I1 = 0.5I2 + 0.5(V1 – 2V2) => V1 = 4I1 + 1.5V2.

Explanation: I1 = V1(Ya + Yab) – V2(Yab) and I2 = -V1(Yab) + V2(Yb + Yab).

4.The [y] parameter of a two port network is given by

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Explanation: The new parameter will be the sum of the previous network and the resistor parameter.

5. The [y] parameter for a 2-port network and the network itself are given below.

The value of Vo/vs is _______

a) 3/32

b) 1/16

c) 2/33

d) 1/17

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7. A 2-port resistive network satisfy the condition A = D = 3/2B = 4/3C. The z11 of the network is

a) 4/3

b) 3/4

c) 2/3

d) 3/2

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Explanation: z11 = A/C = 4/3.

8. A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters are

The Thevenin equivalent circuit presented to the 25 ohm resistor is

a) 80 V, 2.8 ohm

b) 160 V, 6.8 ohm

c) 100 V, 2.4 ohm

d) 120 V, 6.4 ohm

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Explanation: 100 = 25I1 + 2I2, V2 = 40I1 + 10I2

Also V2 = 160I1 + 6.8I2

using above equations we get, Vth = 160 V and Rth = 6.8 ohm.

9. Find V1 and V2.

a) -68.6 V, 114.3 V

b) 68.6 V, -114.3 V

c) 114.3 V, -68.6 V

d) -114.3 V, 68.6 V

View Answer

Explanation: 800 = 10V1 – V2 and 3V2 = 5V1 = 0.

**Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.**

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