Electronic Devices and Circuits Questions and Answers – Method of Analysis

This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Method of Analysis”.

1. What will be the value of V1 in the following circuit?
The value of V1 in the following circuit is 1.5 Vs by applying nodal analysis
a) 0.4 Vs
b) 1.5 Vs
c) 0.67 Vs
d) 2.5 Vs
View Answer

Answer: b
Explanation: Apply nodal analysis, V1 = Vs(4/6 + 1/3)/(1/6 + 1/3 + 1/6) = 1.5 Vs.

2. What will be the value of Va in the following circuit?
The value of Va in the following circuit is 11 V by current division
a) -11 V
b) 11 V
c) 3 V
d) -3 V
View Answer

Answer: b
Explanation: By current division, we get 4A and 1A in resistors 2ohm and 3ohm respectively, applying Kvl in the bottom loop, we have Va = 2(4) + 3(1) = 11V.

3. What will be the value of V1 in the following circuit?
The value of V1 in the following circuit is -90 V
a) 120 V
b) -120 V
c) 90 V
d) -90 V
View Answer

Answer: d
Explanation: -V1/60 – V1/60 + 6 = 9 or V1 = -90 V.
advertisement
advertisement

4. What will be the value of Va in the following circuit?
The value of Va in the following circuit is 8.67 V by current division
a) 4.33 V
b) 4.09 V
c) 8.67 V
d) 8.18 V
View Answer

Answer: c
Explanation: (Va – 10)/4 + Va/2 = 4 or Va = 8.67 V.

5. What will be the value of V2 in the following circuit?
The value of V2 in the following circuit is 2.0 V
a) 0.5 V
b) 1.0 V
c) 1.5 V
d) 2.0 V
View Answer

Answer: d
Explanation: V2/20 + V2+10/30 = 0.5 V or V2 = 2.0 V.

6. What will be the value of I1 in the following circuit?
The value of I1 in the following circuit is 0.1 A by nodal analysis
a) 0.6 A
b) 0.5 A
c) 0.4 A
d) 0.1 A
View Answer

Answer: d
Explanation: By nodal analysis,
0.5=V1/30 + (V1-10)/20
i.e. V1=12V. So i1 = (v1-v2)/20, which gives i1=0.1A.

7. What will be the value of i1 in the following circuit?
The value of i1 in the following circuit is 1.3 A by nodal analysis
a) 0.6 A
b) 2.1 A
c) 1.3 A
d) 1.7 A
View Answer

Answer: c
Explanation: By nodal analysis computing v1 and v2 where
(V1-75)/8 + V1/4 + (V1-V2)/2=0 — (1)
(V1-V2)/2 + [V1-(10*6)]*/(10+5) + V2/3=0 — (2)
*converting current source to voltage source (source transformation)
Hence, i1 = (v1-v2)/2 which gives i1 = 1.3A.
advertisement

8. What will be the value of i1 in the following circuit?
The value of i1 in following circuit is 2.5 mA applying kvl in the rightmost bottom loop
a) 1 mA
b) 1.5 mA
c) 2 mA
d) 2.5 mA
View Answer

Answer: b
Explanation: Applying kvl in the rightmost bottom loop, we have
=> 10k*(i1-7.5) – 75 + 90*i1 = 0
=> 10*i1-75 -75 + 90*i1 = 0
=> 100*i1=150
which gives i1=1.5 mA.

9. What will be the value of i1 in the following circuit?
The value of i1 in the following circuit is 3
a) 4 A
b) 3 A
c) 6 A
d) 5 A
View Answer

Answer: b
Explanation: 3 – 5i1 – 12 => i1 = 3A.
advertisement

10. What will be the value of i1 in the following circuit?
The value of i1 in the following circuit is 15 mA
a) 20 mA
b) 15 mA
c) 10 mA
d) 5 mA
View Answer

Answer: b
Explanation: 45 = 2ki1 + 500(i1 + 15m) => i1 = 15 mA.

Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.

To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.