# Electronic Devices and Circuits Questions and Answers – Method of Analysis

This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Method of Analysis”.

1. What will be the value of V1 in the following circuit? a) 0.4 Vs
b) 1.5 Vs
c) 0.67 Vs
d) 2.5 Vs

Explanation: Apply nodal analysis, V1 = Vs(4/6 + 1/3)/(1/6 + 1/3 + 1/6) = 1.5 Vs.

2. What will be the value of Va in the following circuit? a) -11 V
b) 11 V
c) 3 V
d) -3 V

Explanation: By current division, we get 4A and 1A in resistors 2ohm and 3ohm respectively, applying Kvl in the bottom loop, we have Va = 2(4) + 3(1) = 11V.

3. What will be the value of V1 in the following circuit? a) 120 V
b) -120 V
c) 90 V
d) -90 V

Explanation: -V1/60 – V1/60 + 6 = 9 or V1 = -90 V.

4. What will be the value of Va in the following circuit? a) 4.33 V
b) 4.09 V
c) 8.67 V
d) 8.18 V

Explanation: (Va – 10)/4 + Va/2 = 4 or Va = 8.67 V.

5. What will be the value of V2 in the following circuit? a) 0.5 V
b) 1.0 V
c) 1.5 V
d) 2.0 V

Explanation: V2/20 + V2+10/30 = 0.5 V or V2 = 2.0 V.

6. What will be the value of I1 in the following circuit? a) 0.6 A
b) 0.5 A
c) 0.4 A
d) 0.1 A

Explanation: By nodal analysis,
0.5=V1/30 + (V1-10)/20
i.e. V1=12V. So i1 = (v1-v2)/20, which gives i1=0.1A.

7. What will be the value of i1 in the following circuit? a) 0.6 A
b) 2.1 A
c) 1.3 A
d) 1.7 A

Explanation: By nodal analysis computing v1 and v2 where
(V1-75)/8 + V1/4 + (V1-V2)/2=0 — (1)
(V1-V2)/2 + [V1-(10*6)]*/(10+5) + V2/3=0 — (2)
*converting current source to voltage source (source transformation)
Hence, i1 = (v1-v2)/2 which gives i1 = 1.3A.

8. What will be the value of i1 in the following circuit? a) 1 mA
b) 1.5 mA
c) 2 mA
d) 2.5 mA

Explanation: Applying kvl in the rightmost bottom loop, we have
=> 10k*(i1-7.5) – 75 + 90*i1 = 0
=> 10*i1-75 -75 + 90*i1 = 0
=> 100*i1=150
which gives i1=1.5 mA.

9. What will be the value of i1 in the following circuit? a) 4 A
b) 3 A
c) 6 A
d) 5 A

Explanation: 3 – 5i1 – 12 => i1 = 3A.

10. What will be the value of i1 in the following circuit? a) 20 mA
b) 15 mA
c) 10 mA
d) 5 mA

Explanation: 45 = 2ki1 + 500(i1 + 15m) => i1 = 15 mA.

Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.

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