Electronic Devices and Circuits Questions and Answers – Magneticaly coupled circuits

This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Magneticaly coupled circuits”.

1. For the circuit given below i1 = 4 sin(2t) and i2 = 0. What is the value of v1?
electronic-devices-ciThe value of v1 is 16 cos 2t V if i1 = 4 sin(2t) & i2 = 0
a) -16 cos 2t V
b) 16 cos 2t V
c) 4 cos 2t V
d) -4 cos 2t V
View Answer

Answer: b
Explanation: v1 = 2 d(i1)/dt + d(i2)/dt.

2. For the circuit given below i1 = 4 sin(2t) and i2 = 0. What is the value of v2?
The value of v1 is 16 cos 2t V if i1 = 4 sin(2t) & i2 = 1
a) 2 cos 2t V
b) -2 cos 2t V
c) 8 cos 2t V
d) -8 cos 2t V
View Answer

Answer: c
Explanation: v2 = d(i1)/dt + d(i2)/dt.

3. If i1 = 0 and i2 = 2 sin(4t), the voltage v1 is?
The voltage v1 is 24 cos(4t) V if i1 = 0 & i2 = 2 sin(4t)
a) -24 cos(4t) V
b) 24 cos(4t) V
c) 1.5 cos(4t) V
d) -1.5 cos(4t) V
View Answer

Answer: b
Explanation: v1 = 3 d(i1)/dt – 3 d(i2)/dt.
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4. If i1 = e(-2t) and i2 = 0, the voltage v1 is?
The voltage v1 is 24 cos(4t) V if i1 = 0 & i2 = 2 sin(4t)
a) -6e(-2t) V
b) 6e(-2t) V
c) 1.5e(-2t) V
d) -1.5e(-2t) V
View Answer

Answer: c
Explanation: v1 = 4 d(i1)/dt – 3 d(i2)/dt.

5. If i1 = 3 cos(4t) and and i2 = 0. Find v1.
The voltage v1 is 1.5e(-2t) V if i1 = e(-2t) & i2 = 0
a) -24 sin(4t) V
b) 24 sin(4t) V
c) 1.5 sin(4t) V
d) -1.5 sin(4t) V
View Answer

Answer: a
Explanation: v1 = 2 d(i1)/dt – 2 d(i2)/dt.
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6. If i1 = 3 cos(4t) and and i2 = 0. Find v2.
The voltage v1 is 1.5e(-2t) V if i1 = e(-2t) & i2 = 0
a) -24 sin(4t) V
b) -36 sin(4t) V
c) sin(4t) V
d) -sin(4t) V
View Answer

Answer: a
Explanation: v2 = -3 d(i1)/dt + 2 d(i2)/dt.

7. If i1 = 4 cos(3t) and and i1 = 0. Find v2.
The voltage v1 is 1.5e(-2t) V if i1 = e(-2t) & i2 = 0
a) 12 cos(3t) V
b) -12 cos(3t) V
c) -24 cos(3t) V
d) 24 cos(3t) V
View Answer

Answer: c
Explanation: v1 = 2 d(i1)/dt – 2 d(i2)/dt.
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8. If i2 = 4 cos(3t) and and i1 = 0. Find v2.
The voltage v1 is 1.5e(-2t) V if i1 = e(-2t) & i2 = 1
a) -12 cos(3t) V
b) -24 cos(3t) V
c) -36 cos(3t) V
d) -48 cos(3t) V
View Answer

Answer: c
Explanation: v2 = 3 d(i1)/dt + 2 d(i2)/dt.

9. Leq = ?
Leq = 7 H, L1 + L2 – 2M in the given diagram
a) 4 H
b) 6 H
c) 7 H
d) 0 H
View Answer

Answer: c
Explanation: Leq = L1 + L2 – 2M.
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10. Leq = ?
Leq = 2 H, L1 + L2 – 2M in the given diagram
a) 2 H
b) 4 H
c) 6 H
d) 8 H
View Answer

Answer: a
Explanation: Leq = L1 + L2 – 2M.

Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.

To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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