This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Magneticaly coupled circuits”.
1. For the circuit given below i1 = 4 sin(2t) and i2 = 0. What is the value of v1?
a) -16 cos 2t V
b) 16 cos 2t V
c) 4 cos 2t V
d) -4 cos 2t V
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Explanation: v1 = 2 d(i1)/dt + d(i2)/dt.
2. For the circuit given below i1 = 4 sin(2t) and i2 = 0. What is the value of v2?
a) 2 cos 2t V
b) -2 cos 2t V
c) 8 cos 2t V
d) -8 cos 2t V
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Explanation: v2 = d(i1)/dt + d(i2)/dt.
3. If i1 = 0 and i2 = 2 sin(4t), the voltage v1 is?
a) -24 cos(4t) V
b) 24 cos(4t) V
c) 1.5 cos(4t) V
d) -1.5 cos(4t) V
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Explanation: v1 = 3 d(i1)/dt – 3 d(i2)/dt.
4. If i1 = e(-2t) and i2 = 0, the voltage v1 is?
a) -6e(-2t) V
b) 6e(-2t) V
c) 1.5e(-2t) V
d) -1.5e(-2t) V
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Explanation: v1 = 4 d(i1)/dt – 3 d(i2)/dt.
5. If i1 = 3 cos(4t) and and i2 = 0. Find v1.
a) -24 sin(4t) V
b) 24 sin(4t) V
c) 1.5 sin(4t) V
d) -1.5 sin(4t) V
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Explanation: v1 = 2 d(i1)/dt – 2 d(i2)/dt.
6. If i1 = 3 cos(4t) and and i2 = 0. Find v2.
a) -24 sin(4t) V
b) -36 sin(4t) V
c) sin(4t) V
d) -sin(4t) V
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Explanation: v2 = -3 d(i1)/dt + 2 d(i2)/dt.
7. If i1 = 4 cos(3t) and and i1 = 0. Find v2.
a) 12 cos(3t) V
b) -12 cos(3t) V
c) -24 cos(3t) V
d) 24 cos(3t) V
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Explanation: v1 = 2 d(i1)/dt – 2 d(i2)/dt.
8. If i2 = 4 cos(3t) and and i1 = 0. Find v2.
a) -12 cos(3t) V
b) -24 cos(3t) V
c) -36 cos(3t) V
d) -48 cos(3t) V
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Explanation: v2 = 3 d(i1)/dt + 2 d(i2)/dt.
9. Leq = ?
a) 4 H
b) 6 H
c) 7 H
d) 0 H
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Explanation: Leq = L1 + L2 – 2M.
10. Leq = ?
a) 2 H
b) 4 H
c) 6 H
d) 8 H
View Answer
Explanation: Leq = L1 + L2 – 2M.
Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.
To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.