Electronic Devices and Circuits Questions and Answers – Half-Wave Rectifier

This set of Electronic Devices and Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Half-Wave Rectifier”.

1. The diode in a half wave rectifier has a forward resistance RF. The voltage is Vmsinωt and the load resistance is RL. The DC current is given by _________
a) Vm/√2RL
b) Vm/(RF+RL
c) 2Vm/√π
d) Vm/RL
View Answer

Answer: b
Explanation: For a half wave rectifier, the IDC=IAVG=Im
I= Vmsinωt/(RF+RL)=Imsinωt
Im =Vm/ RF+RL So, IDC=Im/π=Vm/(RF+RL).

2. The below figure arrives to a conclusion that _________
The given op-amp is in inverting mode & makes output voltage to have phase shift of 180°
a) for Vi > 0, V0=-(R2/R1)Vi
b) for Vi > 0, V0=0
c) Vi < 0, V0=-(R2/R1)Vi
d) Vi < 0, V0=0
View Answer

Answer: b
Explanation: The given op-amp is in inverting mode and this makes the output voltage to have a phase shift of 180°. The output voltage is now negative. So, the diode 1 is reverse biased and diode 2 is forward biased. Then output is clearly zero.

3. What is the output as a function of the input voltage (for positive values) for the given figure. Assume it’s an ideal op-amp with zero forward drop (Di=0)
The output as function of the input voltage is Vi for ideal op-amp with zero forward drop
a) 0
b) -Vi
c) Vi
d) 2Vi
View Answer

Answer: c
Explanation: When the input of the inverted mode op-amp is positive, the output is negative.
The diode is reverse biased. The input appears at the output.
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4. In a half wave rectifier, the sine wave input is 50sin50t. If the load resistance is of 1K, then average DC power output will be?
a) 3.99V
b) 2.5V
c) 5.97V
d) 6.77V
View Answer

Answer: b
Explanation: The standard form of a sine wave is Vmsinωt. BY comparing the given information with this equation, Vm =50.
Power=Vm2/RL=50*50/1000=2.5V.

5. In a half wave rectifier, the sine wave input is 200sin300t. The average value of output voltage is?
a) 57.876V
b) 67.453V
c) 63.694V
d) 76.987V
View Answer

Answer: c
Explanation: Comparing with the standard equation, Vm=200V.
Average value is given by, Vavg=Vm/π.
So, 200/π=63.694.

6. Efficiency of a half wave rectifier is
a) 50%
b) 60%
c) 40.6%
d) 46%
View Answer

Answer: c
Explanation: Efficiency of a rectifier is the effectiveness to convert AC to DC. For half wave it’s 40.6%. It’s given by, Vout/Vin*100.

7. If peak voltage for a half wave rectifier circuit is 5V and diode cut in voltage is 0.7, then peak inverse voltage on diode will be?
a) 5V
b) 4.9V
c) 4.3V
d) 6.7V
View Answer

Answer: c
Explanation: PIV is the maximum reverse bias voltage that can be appeared across a diode in the given circuit, If the PIV rating is less than this value of breakdown of diode will occur. For a rectifier, PIV=Vm-Vd=5-0.7=4.3V.
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8. Transformer utilisation factor of a half wave rectifier is _________
a) 0.234
b) 0.279
c) 0.287
d) 0.453
View Answer

Answer: c
Explanation: Transformer utilisation factor is the ratio of AC power delivered to load to the DC power rating. This factor indicates effectiveness of transformer usage by rectifier. For a half wave rectifier, it’s low and equal to 0.287.

9. If the input frequency of a half wave rectifier is 100Hz, then the ripple frequency will be_________
a) 150Hz
b) 200Hz
c) 100Hz
d) 300Hz
View Answer

Answer: c
Explanation: The ripple frequency of the output and input is same. This is because, one half cycle of input is passed and other half cycle is seized. So, effectively the frequency is the same.
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10. Ripple factor of a half wave rectifier is_________(Im is the peak current and RL is load resistance)
a) 1.414
b) 1.21
c) 1.4
d) 0.48
View Answer

Answer: b
Explanation: The ripple factor of a rectifier is the measure of disturbances produced in the output. It’s the effectiveness of a power supply filter to reduce the ripple voltage. The ratio of ripple voltage to DC output voltage is ripple factor which is 1.21.

Sanfoundry Global Education & Learning Series – Electronic Devices and Circuits.

To practice all areas of Electronic Devices and Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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