Analog Electronic Circuits Questions and Answers – BJT Configuration

This set of Analog Circuits Multiple Choice Questions & Answers (MCQs) focuses on “BJT Configuration”.

1. For a BJT, for common base configuration the input characteristics are represented by a plot between which of the following parameters?
a) VBE and IE
b) VBE and IB
c) VCE and IC
d) VCC and IC
View Answer

Answer: a
Explanation: The input signal is applied between the base and the emitter terminals. Input current flowing is the base current and hence characteristics are represented by a plot between VBE and IB.

2. For a BJT, for common base configuration the output characteristics are represented by a plot between which of the following parameters?
a) VBE and IB
b) VCE and IC
c) VCB and IC
d) VCE and IB
View Answer

Answer: c
Explanation: The input signal is applied between the collector and the emitter terminals. Input current flowing is the collector current and hence characteristics are represented by a plot between VCE and IC.

3. In a BJT, if the collector-base junction is reverse-biased and the base-emitter junction is forward-biased, which region is the BJT operating in?
a) Saturation region
b) Active region
c) Cutoff region
d) Reverse active region
View Answer

Answer: b
Explanation: If the collector-base junction is reverse-biased and the base-emitter junction is forward-biased, then the BJT functions in the active region of the output characteristics.
advertisement
advertisement

4. In a BJT, if the collector-base junction is forward-biased and the base-emitter junction is forward-biased, which region is the BJT operating in?
a) Saturation region
b) Active region
c) Cutoff region
d) Reverse active region
View Answer

Answer: a
Explanation: If the collector-base junction and the base-emitter junction are both forward-biased, then the BJT functions in the saturation region of the output characteristics.

5. In a BJT, if the collector-base junction and the base-emitter junction are both reverse-biased, which region is the BJT operating in?
a) Saturation region
b) Active region
c) Cutoff region
d) Reverse active region
View Answer

Answer: c
Explanation: If the collector-base junction and the base-emitter junction are both reverse-biased, then the BJT functions in the cutoff region of the output characteristics.
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

6. From the given characteristics, what is the approximate value of IC at IB=30 uA and VCE=10 V?
Find the approximate value of IC at IB = 30 uA & VCE = 10 V
a) 3 mA
b) 3.4 mA
c) 0 mA
d) 2 mA
View Answer

Answer: b
Explanation: At the intersection of IB=30 uA and VCE=10 V, IC=3.4 mA.

7. From the given characteristics, what is the approximate value of IC at VBE=0.7 V and VCE=15 V?
Find the approximate value of IC at VBE = 0.7 V & VCE = 15 V
a) 3.4 mA
b) 0 mA
c) 2.5 mA
d) 10 mA
View Answer

Answer: c
Explanation: From the characteristics, the value of IB at VBE=0.7V is 20uA. Now, from IB=20 uA, we get IC = 2.5 mA.
advertisement

8. Which of the following correctly determines the relation between α and β?
a) β=α/(1-α)
b) α=β/(1-α)
c) β=α/(1-β)
d) β=α*(1-β)
View Answer

Answer: a
Explanation: α and β are related as β=α/(1-α).
In a BJT, β = IC/IB. and α = IC/IE
β = αIE/IB = (1+β)α
β = α + αβ
β = α/1-α.

9. The value of IC is precisely zero when the value of IE is zero.
a) True
b) False
View Answer

Answer: b
Explanation: When the value of IE is zero, then the value of IC is equal to ICBO which is in the order of microamperes but not zero.
advertisement

10. For common emitter configuration, which of the following is the correct relation?
a) IC < IE
b) IC = βIB
c) IC = αIE
d) IC = IE
View Answer

Answer: d
Explanation: All the relations hold true i.e. IC = βIB and IC = αIE. As α<1, hence IC < IE.

Sanfoundry Global Education & Learning Series – Analog Circuits.

To practice all areas of Analog Circuits, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.