This set of Analog Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Operational Amplifiers”.

1. Which of these is incorrect for an operational amplifier?

a) It has a high voltage gain

b) It is a direct coupled amplifier

c) It is only useful for amplifying AC signals

d) It was originally designed to perform mathematical operations

View Answer

Explanation: Operational amplifier is a high voltage gain, direct coupled amplifier which can be used to perform mathematical operations on analog signals. It can be used to amplify both DC and AC signals.

2. In the given block diagram of an op-amp:

What are A, B, C and D?

a) A = Dual input and balanced output differential amplifier, B = Dual input and unbalanced output differential amplifier, C = Level shifter, D = Power amplifier

b) A = Dual input and balanced output differential amplifier, B = Dual input and balanced output differential amplifier, C = Dual input and unbalanced output differential amplifier, D = Normal amplifier

c) A = Dual input and unbalanced output differential amplifier, B = Dual input and balanced output differential amplifier, C = Voltage regulator, D = Power amplifier

d) A = Normal amplifier, B = Dual input and unbalanced output differential amplifier, C = Level shifter, D = Dual input and balanced output differential amplifier

View Answer

3. In an ideal op-amp, which is not true?

a) Open loop voltage gain is infinite

b) Input resistance is infinite

c) Slew rate is infinite

d) CMRR is zero

View Answer

Explanation: For an ideal op-amp, the open loop voltage gain is infinite. The output resistance is 0 and the input resistance is infinite. Op-amp has zero input current, zero offset voltage, infinite bandwidth, infinite CMRR and infinite slew rate.

4. A practical op-amp has a bandwidth of only 10 Hz. Gain is 10^{6}, and the required bandwidth is 100 kHz. How much feedback is required?

a) 0.99% negative feedback

b) 0.99% positive feedback

c) 1% negative feedback

d) 1% positive feedback

View Answer

Explanation: B2 = B1(1+βA) = 10(1+β10

^{6}) = 100k

1 + β10

^{6}= 10k

β = 9.999×10

^{-3}

In percentage, feedback β = 0.99% negative feedback.

5. Given that for an op-amp the gain is 10^{3}, the slew rate is 1.5V/μsec. Input is 5×10^{-3}sinωt, calculate maximum frequency to prevent distortion.

a) 47.7 kHz

b) 0.3 MHz

c) 477 Hz

d) 3 kHz

View Answer

Explanation: dV

_{OUT(max)}/dT =< Slew rate

A.Vmω =< 1.5 V/μsec

10

^{3}.5.10

^{-3}.ω = < 1.5×10

^{6}

ω=<0.3×10

^{6}

Frequency f = 0.0477×10

^{6}Hz

6. Given that CMRR is 100dB. Input common-mode voltage is 12 V. Differential voltage gain is 4000. Calculate output common-mode voltage.

a) 48V

b) 0.48V

c) 20V

d) 11V

View Answer

Explanation: CMRR = 20 log(A

_{D}/A

_{CM}) = 20 log(4000×12/V

_{ocm}) = 100

Log(48000/V

_{OCM}) = 5

48000/V

_{OCM}= 10

^{5}

V

_{OCM}= 0.48V.

7. The unity gain bandwidth for an op-amp having open loop gain 2×10^{6} is 10 Mhz. Calculate the AC gain of op-amp at an input of 2000 Hz.

a) 2000

b) 5000

c) 10000

d) 12.5

View Answer

Explanation: UGB = A

_{OL}f

_{OL}

f

_{OL}= 10M/2×10

^{6}= 5Hz

The AC gain |A| = \(\frac{AOL}{\sqrt{1+(f/5)^2}}\)

|A| = 2×10

^{6}/400 = 5000.

8. Given that:

A: Voltage gain of op-amp decreases at high frequencies

B: Its internal structure uses a capacitor

a) Both A and B are correct, and B is the correct reason for A

b) Both A and B are correct, but B is not the correct reason for A

c) A is correct and B is incorrect

d) A is incorrect and B is correct

View Answer

Explanation: The internal structure of an op-amp uses a compensation capacitor for stability purpose. It provides dominant pole compensation; thereby the op-amp remains stable. However, the op-amp gain remains constant at low frequencies but decreases at high frequencies due to a compensation capacitor.

9. Till what frequency do we get amplification from IC 741?

a) Unity gain bandwidth

b) 3-dB frequency

c) Infinity

d) UGB + f_{OL}

View Answer

Explanation: The 3dB frequency is the cut-off frequency, where the gain is \(\frac{1}{\sqrt{2}}\) of the maximum. The gain is only constant for infinite frequency, that is, has infinite bandwidth if the op-amp is ideal, which practically doesn’t exist. The UGB is the point at which gain of op-amp reaches 1.

10. What is the use of the compensation capacitor in op-amp?

a) Improves the amplification of op-amp

b) Decreases the slew rate of op-amp

c) Increases the bandwidth of op-amp

d) Op-amp acts as all pass filter

View Answer

Explanation: Compensation capacitor in the internal structure of op-amp to improve its frequency response, increasing its stability. It also decreases the slew rate of the op-amp.

**Sanfoundry Global Education & Learning Series – Analog Circuits.**

To practice all areas of Analog Circuits, __here is complete set of 1000+ Multiple Choice Questions and Answers__.