This set of Analog Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Constant Voltage Drop Model-1”.

1. In constant voltage drop model diode in forward bias is considered as a

a) Resistor

b) Perfect conductor

c) Perfect insulator

d) Capacitor

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Explanation: In constant voltage drop model the diode is considered as a perfect conductor in forward bias and perfect insulator in reverse bias. That is voltage drop at forward bias is zero and current through the diode at reverse bias is zero. In this model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

2. In constant voltage drop diode in reverse bias is considered as a

a) Resistor

b) Perfect conductor

c) Perfect insulator

d) Capacitor

View Answer

Explanation: In constant voltage drop the diode is considered as a perfect conductor in forward bias and perfect insulator in reverse bias. That is voltage drop at forward bias is zero and current through the diode at reverse bias is zero. In this model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

3. The current I through the circuit if we consider diode in constant voltage drop model is

(Take V_{D} as 0.5V)

a) 2mA

b) 2.5mA

c) 3.5mA

d) 1mA

View Answer

Explanation: In constant voltage drop model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

Since D1 is in forward biased there will be a voltage drop of 0.5V. So net voltage will be 2.5V and hence current is 2.5mA.

4. The voltage across the diode V_{out} if V_{in} is -5V and resistance is 10K is

(Use constant voltage drop model of diode and take V_{D} as 0.5V)

a) -3V

b) 0V

c) -5V

d) -2.5V

View Answer

Explanation: In constant voltage drop model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

Since diode is reverse biased entire voltage will appear across diode.

5. The voltage across the diode V_{out} if V_{in} is 5V and resistance is 10K is

(Use constant voltage drop model of diode and take V_{D} as 0.5V)

a) 5V

b) 0.5V

c) 2.5V

d) 0V

View Answer

Explanation: In constant voltage drop model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

Since diode is forward biased and potential is greater than V

_{D}voltage across diode is V

_{D}.

6. The current I through the circuit I if voltage v is -3V is

(Use constant voltage drop model of diode and take V_{D} as 0.5V)

a) 10mA

b) 1mA

c) 3mA

d) 0mA

View Answer

Explanation: In constant voltage drop model, in forward bias, the diode can be replaced as a cell and a short circuit, and in reverse bias as an open circuit. In above circuit, the diode is reverse biased, hence when open circuited, no current flows.

7. If current source produces a current of 1mA and resistance R is 3K then voltage across the resistor is

(Use constant voltage drop model of diode and take V_{D} as 0.5V)

a) 3V

b) 0V

c) 0.5V

d) 0.3V

View Answer

Explanation: In constant voltage drop model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

The diode is forward biased and drop across it is 0.5V. Maximum current flows through the diode and thus the voltage across diode is same as that across the resistor = 0.5V.

8. If resistance R_{1} is 10K, V_{2} = 2V, V_{1} = 3V then the current I through the circuit will be

(Use constant voltage drop model of diode and take V_{D} as 0.5V)

a) 0.3mA

b) 0.6mA

c) 0.7mA

d) 0.1mA

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Explanation: In ideal diode model the diode is considered as a perfect conductor in forward bias and perfect insulator in reverse bias. That is voltage drop at forward bias is zero and current through the diode at reverse bias is zero.

Since both voltage is reverse bias to diode the diode will disappear from the circuit. Then effective voltage becomes 3-2 = 1V so current is 1/10K = 0.1mA.

9. If resistance R_{1} is 10K, V_{2} = -2V, V_{1} = -3V then the current I through the circuit will be

(Use constant voltage drop model of diode and take V_{D} as 0.5V)

a) 0.5mA

b) 0.25mA

c) 2mA

d) 3mA

View Answer

Explanation: In constant voltage drop model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

Since both voltage sources are forward biased the diode V

_{2}and diode can be replaced by a single cell of V

_{D}. So net voltage in the circuit is 2.5V. So the current will be 0.25mA.

10. What will be the voltage V_{out} if V_{A} = 3V and V_{B} = -5V?

(Use constant voltage drop model of diode and take V_{D} as 0.5V)

a) 2.5

b) 3.5

c) -5.5

d) -4.5

View Answer

Explanation: In constant voltage drop model at forward bias diode can be replaced as a cell and in reverse bias diode can be avoided by considering the terminals are open.

Since first diode is forward biased and second diode reverse bias, we can ignore the second diode. Drop across the first diode is 0.5V and hence net voltage at output is 3-0.5=2.5V.

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