This set of Linear Algebra Questions and Answers for Freshers focuses on “Rank of Matrix in Row Echelon Form”.
1. Write Matrix corresponding to the following linear transformations.
y1=2x1-x2-x3
y2=3x3
y3=x1+x2
a) \(\begin{bmatrix}2&-1&-1\\0&0&3\\1&1&0\end{bmatrix}\)
b) \(\begin{bmatrix}2&-1&-1\\0&0&3\\1&0&0\end{bmatrix}\)
c) \(\begin{bmatrix}2&-1&-1\\0&0&3\\1&1&1\end{bmatrix}\)
d) \(\begin{bmatrix}2&-1&-1\\0&1&3\\1&1&0\end{bmatrix}\)
View Answer
Explanation: In the given question,
We know that Linear Transformation is given by,
\(\begin{bmatrix}y1\\y2\\y3\end{bmatrix}\begin{bmatrix}2&-1&-1\\0&0&3\\1&1&0\end{bmatrix}\begin{bmatrix}x1\\x2\\x3\end{bmatrix}\)
Thus, the matrix for linear transformation is
\(\begin{bmatrix}2&-1&-1\\0&0&3\\1&1&0\end{bmatrix}\).
2. Which of the following Linear Transformations is not correct for the given matrix?
\(\begin{bmatrix}1&2&-3\\-1&0&1\\2&1&0\end{bmatrix}\)
a) x1=1y1-3y2-3y3
b) x1=1y1-2y2-3y3
c) x2=-1y1+1y3
d) x3=2y1+y2
View Answer
Explanation: In the given question,
X=\(\begin{bmatrix}1&2&-3\\-1&0&1\\2&1&0\end{bmatrix}\)Y
Thus,
x1=1y1-2y2-3y3
x2=-1y1+1y3
x3=2y1+y2.
3. For the linear transformation, X=\(\begin{bmatrix}2&1&1\\1&1&2\\1&0&-2\end{bmatrix}\)Y, find the Y co-ordinates for (1, 2, -1) in X.
a) (0, -2, 0)
b) (-1, 3, 1)
c) (-1, -2, 0)
d) (-1, 3, 0)
View Answer
Explanation: In the given question,
X=(1, 2, -1)
\(\begin{bmatrix}1\\2\\-1\end{bmatrix}\begin{bmatrix}2&1&1\\1&1&2\\1&0&-2\end{bmatrix}\begin{bmatrix}y1\\y2\\y3\end{bmatrix}\)
y1– 2y3=-1
y2+4y3=3
y3=0
Thus Y (-1, 3, 0).
Sanfoundry Global Education & Learning Series – Linear Algebra.
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