This set of Structural Analysis Multiple Choice Questions & Answers (MCQs) focuses on “Influence Lines for Beams”.
1. If on ILD analysis peak force comes out to be 2 KN, then what will be the peak force if loading is 2KN?
a) 1 KN
b) 2 KN
c) 3 KN
d) 4 KN
View Answer
Explanation: Peak force will be load multiplied by earlier peak load i.e. 2*2.
2. What will be the equation of the ILD of shear force at point C for the CB part of the beam, where AC = 1m and CB = 3m?
a) 0.75 – 0.375X
b) 0.75 – 0.475X
c) 0.85 – 0.375X
d) 0.75 – 0.1375X
View Answer
Explanation: Just assume force at any point between BC and conserve moment about point B.
3. What will be the equation of the ILD of shear force at point C for the AC part of the beam, where AC = 1m and CB = 3m?
a) .25X – 1.25
b) .25X – 2.25
c) .25X – .25
d) .25X + .25
View Answer
Explanation: Just assume force at any point between AC and conserve moment about point A.
4. If a concentrated load is to be applied on the below-shown beam such that the shear at point C becomes maximum, where should the load be applied?
a) At A
b) At B
c) At C
d) Midway between A and C
View Answer
Explanation: If we draw ILD according to the above given equations, we will see that peak of ILD comes at point C.
5. If a concentrated load of 50 kN is applied at point C, then what will be the shear developed at point C?
a) 17.5 KN
b) 27.5 KN
c) 37.5 KN
d) 47.5 KN
View Answer
Explanation: Position of ILD at point C is 0.75 (peak). So, shear developed will be 0.75 multiplied by 50KN.
6. What will be the shear developed at point C if a uniform load of 10 kN/m is applied between point B and C?
a) 10.25 KN
b) 11.25 KN
c) 12.25 KN
d) 13.25 KN
View Answer
Explanation: In case of uniform load, area of ILD curve multiplied by uniform load gives the shear.
7. If both, a load of 50 kN at point C and a uniform load of 10 kN/m between CB act, then what will be the shear generated at point C?
a) 48.75
b) 50.75
c) 46.75
d) 52.75
View Answer
Explanation: Net shear generated will be the sum of individually generated shear which has been already calculated earlier.
8. What will be the ILD equation for shear at point B in a beam with AB = 2m, BC = 3m, and CD = 3m, where B is a pin support and D is a roller support?
a) 1.33 – 0.116625X
b) 2.33 – 0.16625X
c) 3.33 – 0.16625X
d) 1.33 – 0.16625X
View Answer
Explanation: Apply a unit load at any point at a distance X and conserve the moment about point D. The resulting equation represents the shear force at point B.
9. What will be the ILD equation for shear at point C for the AB part of the beam with AB = 2m, BC = 3m, and CD = 3m, where B is a pin support and C is an arbitrary point on the beam?
a) -0.33 + 0.165X
b) -0.33 + 0.265X
c) -0.43 + 0.165X
d) -0.33 + 0.365X
View Answer
Explanation: Apply a unit load between points A and B and conserve the moment about point B. The equation represents the shear force at point C for the AB part of the beam.
10. What will be the ILD equation for shear at point D in a beam with AB = 2m, BC = 3m, and CD = 3m, where B is a pin support and D is a roller support?
a) -.43 + 0.16625X
b) -.33 + 0.16625X
c) -.53 + 0.16625X
d) -.33 + 0.216625X
View Answer
Explanation: Apply a unit load at any point and conserve the moment about point B. This yields the equation for the shear force at point D.
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