Structural Analysis Questions and Answers – Portal Frames Numericals

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This set of Structural Analysis Multiple Choice Questions & Answers (MCQs) focuses on “Portal Frames Numericals”.

1. Vertical reaction at support B for the given frame is ______

a) 10kN (Upward)
b) 10kN (Downward)
c) 26kN (Upward)
d) 26kN (Downward)
View Answer

Answer: c
Explanation:

∑Mb=0
Vb*3-36*1.5-24*1=0
Vb=26kN (Upward)
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2. Vertical reaction at support A for the given frame is ______

a) 10kN (Upward)
b) 10kN (Downward)
c) 26kN (Upward)
d) 26kN (Downward)
View Answer

Answer: a
Explanation:

∑V=0
Va+Vb=36kN
Vb=36-26=10kN (Downward)

3. Moment at support A for the given frame is ______

a) 30kNm (Clockwise)
b) 30kNm (Anticlockwise)
c) 24kNm (Clockwise)
d) 24kNm (Anticlockwise)
View Answer

Answer: d
Explanation:
Ma=26*3-36*1.5-24*5+30*4
Ma =24kNm (Clockwise)
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4. Horizontal reaction at support A for the given frame is ______

a) 3kN (Leftward)
b) 3kN (Rightward)
c) 6kN (Leftward)
d) 6kN (Rightward)
View Answer

Answer: c
Explanation:

∑H= 0
Ha+24=30
Ha=6 kN (Rightward)

5. Bending Moment Diagram for member AB in the given set of frame is given by ________

a)
b)
c)
d)
View Answer
Answer: c
Explanation: Support A is a fixed having clockwise moment of 24 kNm, but as we proceed along the AB, horizontal force in rightward direction gives anticlockwise moment. Hence, moment at joint B is 24 – 6*4 = 0kNm.

6. Bending Moment Diagram for member AB in the given set of frame is given by _________

a)
b)
c)
d)
View Answer

Answer: b
Explanation: Support B is a roller support and does not have any horizontal reaction, thus bending moment would continue to be zero until and unless any external horizontal forces acts upon it. Thus bending moment will be maximum at joint C, Mc = 60kNm.

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7. What is the support reaction of C for the given frame?

a) 10.5kN (Upward)
b) 10.5kN (Downward)
c) 37.5kN (Upward)
d) 37.5kN (Downward)
View Answer

Answer: c
Explanation:

∑Mb=0
Vc*4=48*2+36*1.5
Vc=37.5 KN

8. What is vertical support reaction at support A for the given frame?

a) 10.5kN (Upward)
b) 10.5kN (Downward)
c) 37.5kN (Upward)
d) 37.5kN (Downward)
View Answer

Answer: a
Explanation:

∑V=0
Va+37.5=48
Va=10.5 KN

9. Calculate moment at support at for the given frame.

a) 108kNm (Clockwise)
b) 108kNm (Anticlockwise)
c) 276kNm (Clockwise)
d) 276kNm (Anticlockwise)
View Answer
Answer: c
Explanation:
Moment at A=Ma=56*6-20*3=276 KNm

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10. Axial force diagram for the member AB for the given frame is given by ________

a)
b)
c)
d)
View Answer

Answer: b
Explanation: Since the vertical reaction at the support A is 10.5kN, which is compressive in nature. Therefore, Axial Force Diagram is given by the following figure.

11. Which one of the following is correct shear force diagram for member AB for the given frame?

a)
b)
c)
d)
View Answer

Answer: a
Explanation: Horizontal support reaction at support A is 56kN and at 3metre above the support horizontal force of 20kN is acting leftward thus reducing shear force diagram value to 36kN.
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12. Which one of the following is correct bending moment diagram for member AB for the given frame?

a)
b)
c)
d)
View Answer

Answer: a
Explanation: Since there’s no external uniformly distributed force is acting on the member, option c and d can be directly eliminated. Bending at support A is 276kNm given by
Moment at A=Ma=56*6-20*3=276 KNm

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He is Linux Kernel Developer & SAN Architect and is passionate about competency developments in these areas. He lives in Bangalore and delivers focused training sessions to IT professionals in Linux Kernel, Linux Debugging, Linux Device Drivers, Linux Networking, Linux Storage, Advanced C Programming, SAN Storage Technologies, SCSI Internals & Storage Protocols such as iSCSI & Fiber Channel. Stay connected with him @ LinkedIn | Youtube | Instagram | Facebook | Twitter