This set of Structural Analysis Multiple Choice Questions & Answers (MCQs) focuses on “Internal Loadings at a Specified Point-1”.
1. How has the most popular sign convention for force direction been decided?
a) Logically
b) Arbitrary
c) Easiest to use
d) There is no popular sign convention
View Answer
Explanation: The most popular sign convention has been decided arbitrarily, but it has become the most commonly used convention in practice.
2. What will be the internal force generated at hinge B due to the above loading, where all supports are roller type and points B and D are hinges, and the lengths of segments AB, BC, CD, DE, EF, and FG are all 2m?
a) 5
b) 10
c) 15
d) 20
View Answer
Explanation: By cutting out the section from point A to B (since B is a hinge), and balancing the moment about point A, the internal force at hinge B is determined to be 10 kN.
3. What will be the internal force generated at hinge D due to the above loading, where all supports are roller type and points B and D are hinges, and the lengths of segments AB, BC, CD, DE, EF, and FG are all 2m?
a) 5
b) 10
c) 15
d) 20
View Answer
Explanation: By separating the section from point B to D, and balancing the moment about point C, the internal force at hinge D is determined to be 10 kN.
4. What will be the support force due to point C, where all supports are roller type and points B and D are hinges, and the lengths of segments AB, BC, CD, DE, EF, and FG are all 2m?
a) 5
b) 10
c) 15
d) 20
View Answer
Explanation: The support force at point C can be found by balancing the forces in the section between both hinges, resulting in 20 kN.
5. What will be the support reaction generated by support A, where all supports are roller type and points B and D are hinges, and the lengths of segments AB, BC, CD, DE, EF, and FG are all 2m?
a) 5
b) 10
c) 15
d) 20
View Answer
Explanation: The support reaction at point A can be found by balancing the forces in the section between joints A and B, resulting in a reaction force of 10 kN.
6. What will be the support reaction generated by support E, where all supports are roller type and points B and D are hinges, and the lengths of segments AB, BC, CD, DE, EF, and FG are all 2m?
a) 5
b) 7.5
c) 10
d) 12.5
View Answer
Explanation: The support reaction at point E can be found by balancing the moment about point G in the section between joints D and F, resulting in a reaction force of 7.5 kN.
7. What will be the support reaction generated by support G, where all supports are roller type and points B and D are hinges, and the lengths of segments AB, BC, CD, DE, EF, and FG are all 2m?
a) 5
b) 7.5
c) 10
d) 12.5
View Answer
Explanation: The support reaction at point G can be determined by balancing the forces in the section between joints D and F, resulting in a reaction force of 12.5 kN.
8. What will be the internal force in y direction at joint B, where point A is a pin support, point D is a roller-type support, and a uniform horizontal load of 80 kN/m is acting on beam AB, with AB = 5m, BC = CD = 2m?
a) 5
b) 10
c) 15
d) 20
View Answer
Explanation: The internal force in the y-direction at joint B is determined by analyzing the beam and the applied load, which results in an internal force of 10 kN.
9. What will be the internal force in x direction at joint B, where point A is a pin support, point D is a roller-type support, and a uniform horizontal load of 80 kN/m is acting on beam AB, with AB = 5m, BC = CD = 2m?
a) 0
b) 20
c) 30
d) 40
View Answer
Explanation: Since the applied load is horizontal, the internal force in the x-direction at joint B will be zero, as no vertical forces are acting in this direction.
10. What will be the internal moment generated at joint B due to the above-shown loading, where point A is a pin support, point D is a roller-type support, and a uniform horizontal load of 80 kN/m is acting on beam AB, with AB = 5m, BC = CD = 2m?
a) 170
b) 340
c) 510
d) 680
View Answer
Explanation: The internal moment at joint B is calculated by considering the applied horizontal load and the distances between the supports, resulting in a moment of 340 kN·m.
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