Parabola - Conic Sections - Class 11 Maths MCQ

This set of Class 11 Maths Chapter 11 Multiple Choice Questions & Answers (MCQs) focuses on “Conic Sections – Parabola – 1”.

1. Find the focus of parabola with equation y²=100x.
a) (0, 25)
b) (0, -25)
c) (25, 0)
d) (-25, 0)
View Answer

Answer: c
Explanation: Comparing equation with y²=4ax.
4a=100 => a=25.
Focus is at (a, 0) i.e. (25, 0).

2. Find the focus of parabola with equation y²=-100x.
a) (0, 25)
b) (0, -25)
c) (25, 0)
d) (-25, 0)
View Answer

Answer: d
Explanation: Comparing equation with y²=-4ax.
4a=100 => a=25.
Focus is at (-a, 0) i.e. (-25, 0).

3. Find the focus of parabola with equation x²=100y.
a) (0, 25)
b) (0, -25)
c) (25, 0)
d) (-25, 0)
View Answer

Answer: a
Explanation: Comparing equation with x²=4ay.
4a=100 => a=25.
Focus is at (0, a) i.e. (0, 25).

4. Find the focus of parabola with equation x²=-100y.
a) (0, 25)
b) (0, -25)
c) (25, 0)
d) (-25, 0)
View Answer

Answer: b
Explanation: Comparing equation with x²=-4ay.
4a=100 => a=25.
Focus is at (0, -a) i.e. (0, -25).

5. Find the equation of latus rectum of parabola y²=100x.
a) x=25
b) x=-25
c) y=25
d) y=-25
View Answer

Answer: a
Explanation: Comparing equation with y²=4ax.
4a=100 => a=25. Line passing through focus perpendicular to axis is latus rectum.
Equation of latus rectum is x=a => x=25.

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6. Find the equation of latus rectum of parabola y²=-100x.
a) x=25
b) x=-25
c) y=-25
d) y=25
View Answer

Answer: b
Explanation: Comparing equation with y²=-4ax.
4a=100 => a=25. Line passing through focus perpendicular to axis is latus rectum.
Equation of latus rectum is x=-a => x=-25.

7. Find the equation of latus rectum of parabola x²=100y.
a) x=25
b) x=-25
c) y=-25
d) y=25
View Answer

Answer: d
Explanation: Comparing equation with x²=4ay.
4a=100 => a=25. Line passing through focus perpendicular to axis is latus rectum.
Equation of latus rectum is y=a => y=25.

8. Find the equation of latus rectum of parabola x²=-100y.
a) x=25
b) x=-25
c) y=-25
d) y=25
View Answer

Answer: c
Explanation: Comparing equation with x²=-4ay.
4a=100 => a=25. Line passing through focus perpendicular to axis is latus rectum.
Equation of latus rectum is y=-a => y=-25.

9. Find the equation of directrix of parabola y²=100x.
a) x=25
b) x=-25
c) y=25
d) y=-25
View Answer

Answer: b
Explanation: Comparing equation with y²=4ax.
4a=100 => a=25. Directrix is a line parallel to latus rectum in such a way that vertex is at middle of both.
Equation of directrix is x=-a => x=-25.

10. Find the equation of directrix of parabola y²=-100x.
a) x=25
b) x=-25
c) y=-25
d) y=25
View Answer

Answer: a
Explanation: Comparing equation with y²=-4ax.
4a=100 => a=25. Directrix is a line parallel to latus rectum in such a way that vertex is at middle of both.
Equation of directrix is x=a => x=25.

Sanfoundry Global Education & Learning Series – Mathematics – Class 11.

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