# Class 11 Maths MCQ – Sequences and Series

This set of Class 11 Maths Chapter 9 Multiple Choice Questions & Answers (MCQs) focuses on “Sequences and Series”. These MCQs are created based on the latest CBSE syllabus and the NCERT curriculum, offering valuable assistance for exam preparation.

1. Sequence is same as progression.
a) True
b) False

Explanation: Sequence and progression are different things. When sequence follow a specified pattern, it is said to be a progression.

2. Complete 2,3,5,7, _____________
a) 8
b) 9
c) 10
d) 11

Explanation: Since 2,3,5 and 7 all are consecutive prime numbers so, it is a sequence of prime numbers. Prime number next to 7 is 11. So, 2,3,5,7,11.

3. Complete 2, 4, 6, 8, _____________
a) 10
b) 9
c) 13
d) 11

Explanation: Since 2,4,6 and 8 are even numbers so it is a sequence of even numbers. Even number next to 8 is 10. So, 2,4,6,8,10.

4. Which of the following is finite sequence?
a) 48,24,12, ………….
b) 1,2,3, …………
c) 2,4,6,8,10
d) 2,3,5,7,11,13, ……………………

Explanation: Since sequence 2,4,6,8,10 contains limited number of terms so, it is finite sequence. Rest all are infinite sequences.

5. Which of the following relation gives Fibonacci sequence?
a) an = an-1 + an-2
b) an-1 = an + an-2
c) an-2 = an + an-1
d) an = an+1 + an-2

Explanation: an = an-1 + an-2, n>2.
This is a recurrence relation which gives Fibonacci sequence.

6. 1,1,2,3,5, ………… is a Fibonacci Sequence.
a) True
b) False

Explanation: Yes, 1,1,2,3,5, ………… is a Fibonacci Sequence because it follows the recurrence relation
an = an-1 + an-2, n>2.

7. What is the first term of Fibonacci sequence?
a) 0
b) 1
c) 2
d) 3

Explanation: a1=1 and a2=1.
an = an-1 + an-2, n>2.
This is a recurrence relation which gives the Fibonacci sequence.

8. What is the third term of Fibonacci sequence?
a) 0
b) 1
c) 2
d) 3

Explanation: a1=1 and a2=1.
an = an-1 + an-2, n>2.
This is a recurrence relation which gives Fibonacci sequence.
=>a3=a1+a2=1+1=2.

9. If an = 4n+6, find 15th term of the sequence.
a) 6
b) 10
c) 60
d) 66

Explanation: an = 4n+6 and n=15
=>a15 = 4*15 + 6 = 60+6 = 66.

10. a1 = a2 = 2, an = an – 1–1, n > 2. Find a5.
a) 2
b) -1
c) 1
d) 0

Explanation: an = an – 1–1, n > 2
=> a3 = a2 – 1 = 2 – 1 = 1
=> a4 = a3 – 1 = 1 – 1 = 0
=> a5 = a4 – 1 = 0 – 1 = -1.

More MCQs on Class 11 Maths Chapter 9:

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