Mathematics Questions and Answers – Statistics – Analysis of Frequency Distributions

«
»

This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Statistics – Analysis of Frequency Distributions”.

1. An analysis of the monthly wages paid to the workers of a form is given below. Calculate the total monthly wages.

No. of workers 100
Average monthly wages 280
Variance of distribution of wages 10
advertisement

a) 2800
b) 280
c) 28000
d) 2.8
View Answer

Answer: c
Explanation: Number of wage earners (n1) = 100
Mean of monthly wages (X1) = ₹280
Mean of monthly wages = Total monthly wage/Number of workers
⇒ 280 = total monthly wages/100
⇒ Total monthly wages = 28000.

2. If the coefficient of variation is 100 the mean of the data is 25, then find the standard deviation.
a) 5
b) 10
c) 15
d) 25
View Answer

Answer: d
Explanation: Coefficient of Variance = (Standard Deviation/Mean) × 100
⇒ Standard Deviation = 25.
advertisement
advertisement

3. If the standard deviation of a data is 820 and mean of the data is 50, find the coefficient of variation.
a) 16.4
b) 164
c) 1640
d) 1.64
View Answer

Answer: a
Explanation: Coefficient of Variance = (Standard Deviation/Mean) × 100
⇒ Coefficient of Variance = (820/50) × 100 = 16.4.

4. If standard deviation of a data is 40 and the coefficient of variation is 25600, then find the mean.
a) 64
b) 6.4
c) 640
d) 0.64
View Answer

Answer: b
Explanation: Coefficient of Variance = (Standard Deviation/Mean) × 100
⇒ Mean = 25600/4000 = 6.4.
advertisement

5. The following data shows the heights and weights of the students of class 9. Which of the following is correct?

Height Weight
Mean 170 cm 55 kg
Variance 130 cm2 25 kg2

a) Coefficient of variation of weights > Coefficient of variation of heights
b) Coefficient of variation of weights < Coefficient of variation of heights
c) Coefficient of variation of weights = Coefficient of variation of heights
d) Coefficient of variation of weights = ½ Coefficient of variation of heights
View Answer

Answer: a
Explanation: X̄1 = 170, X̄2 = 55, σ12 = 130 and σ22 = 25.
Now, Standard Deviation = √Variance
⇒ Standard deviation of height, σ12 = 130 ⇒ σ1 = √130 ⇒ σ1 = 11.40
and Standard deviation of weight, σ22 = 130 ⇒ σ2 = √25 ⇒ σ2 = 5
Also, Coefficient of Variance = (Standard Deviation/Mean) × 100
⇒ Coefficient of Variation in heights = (σ1/X̄1) x 100 = (11.40/170) x 100 = 6.7
and Coefficient of Variation in weights = (σ2/X̄2) x 100 = (5/55) x 100 = 9.09.
advertisement

Sanfoundry Global Education & Learning Series – Mathematics – Class 11.

To practice all areas of Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

advertisement

Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

advertisement
advertisement
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He is Linux Kernel Developer & SAN Architect and is passionate about competency developments in these areas. He lives in Bangalore and delivers focused training sessions to IT professionals in Linux Kernel, Linux Debugging, Linux Device Drivers, Linux Networking, Linux Storage, Advanced C Programming, SAN Storage Technologies, SCSI Internals & Storage Protocols such as iSCSI & Fiber Channel. Stay connected with him @ LinkedIn | Youtube | Instagram | Facebook | Twitter