This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Three Dimensional Geometry – Section Formula”.

1. Find midpoint of (1, 4, 6) and (5, 8, 10).

a) (6, 12, 8)

b) (3, 6, 8)

c) (1, 9, 12)

d) (4, 9, 12)

View Answer

Explanation: We know, midpoint of (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) is (x

_{1}+x

_{2}) /2, (y

_{1}+y

_{2}) /2, (z

_{1}+z

_{2})/2).

So, midpoint of (1, 4, 6) and (5, 8, 10) is ((1+5)/ 2, (4+8)/ 2, (6+10)/2) is (3, 6, 8).

2. The coordinates of a point dividing the line segment joining (1, 2, 3) and (4, 5, 6) internally in the ratio 2:1 is ____________________

a) (3, 4, 5)

b) (5, 4, 3)

c) (5, 3, 4)

d) (4, 5, 3)

View Answer

Explanation: The coordinates of a point dividing the line segment joining (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) internally in the ratio m : n is \((\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n},\frac{mz_2+nz_1}{m+n})\).

So, the coordinates of a point dividing the line segment joining (1, 2, 3) and (4, 5, 6) internally in the ratio 2:1 is \((\frac{2*4+1*1}{2+1},\frac{2*5+1*2}{2+1},\frac{2*6+1*3}{2+1})\) = (3, 4, 5).

3. In which ratio (3, 4, 5) divides the line segment joining (1, 2, 3) and (4, 5, 6) internally?

a) 1:2

b) 2:1

c) 3:4

d) 4:3

View Answer

Explanation: The coordinates of a point dividing the line segment joining (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) internally in the ratio m: n is \((\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n},\frac{mz_2+nz_1}{m+n})\).

Let the ratio be k : 1.So, the coordinates of a point dividing the line segment joining (1, 2, 3) and (4, 5, 6) internally in the ratio k: 1 is \((\frac{k*4+1*1}{k+1},\frac{k*5+1*2}{k+1},\frac{k*6+1*3}{k+1})\)

=> \((\frac{k*4+1*1}{k+1},\frac{k*5+1*2}{k+1},\frac{k*6+1*3}{k+1})\) is same as (3, 4, 5).

=> (4k+1)/(k+1) = 3

=> 4k+1 = 3k+3

=> k = 2

So, ratio is 2:1.

4. The coordinates of a point dividing the line segment joining (1, 2, 3) and (4, 5, 6) externally in the ratio 2:1 is ____________________

a) (4, 5, 6)

b) (6, 8, 9)

c) (7, 8, 9)

d) (8, 6, 4)

View Answer

Explanation: The coordinates of a point dividing the line segment joining (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) externally in the ratio m : n is \((\frac{mx_2-nx_1}{m-n},\frac{my_2-ny_1}{m-n},\frac{mz_2-nz_1}{m-n})\).

So, the coordinates of a point dividing the line segment joining (1, 2, 3) and (4, 5, 6) externally in the ratio 2:1 is \((\frac{2*4-1*1}{2-1},\frac{2*5-1*2}{2-1},\frac{2*6-1*3}{2-1})\) = (7, 8, 9).

5. If coordinates of vertices of a triangle are (7, 6, 4), (5, 4, 6), (9, 5, 8), find the coordinates of centroid of the triangle.

a) (7, 5, 3)

b) (7, 3, 5)

c) (5, 3, 7)

d) (3, 5, 7)

View Answer

Explanation: If coordinates of vertices of a triangle are (x

_{1}, y

_{1}, z

_{1}), (x

_{2}, y

_{2}, z

_{2}), (x

_{3}, y

_{3}, z

_{3}) the coordinates of centroid of the triangle are ((x

_{1}+x

_{2}+x

_{3})/3, (y

_{1}+y

_{2}+y

_{3})/3, (z

_{1}+z

_{2}+z

_{3})/3)

So, coordinates of centroid of the given triangle are ((7+5+9)/3, (6+4+5)/3, (4+6+8)/3) = (7, 5, 3).

6. The ratio in which line joining (1, 2, 3) and (4, 5, 6) divide X-Y plane is ________

a) 2

b) -2

c) 1/2

d) -1/2

View Answer

Explanation: The coordinates of a point dividing the line segment joining (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) internally in the ratio m : n is \((\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n},\frac{mz_2+nz_1}{m+n})\).

Let ratio be k : 1.

So, z-coordinate of the point will be (k*6+1*3)/(k+1).

We know, for X-Y plane, z coordinate is zero.

(6k+1*3)/(k+1) = 0 => k=-1/2

7. Find the points which trisects the line joining (4, 9, 8) and (13, 27, -4).

a) (7, 4, 15)

b) (7, 15, 4)

c) (4, 15, 7)

d) (4, 7, 15)

View Answer

Explanation: Points which trisect the line divides it into 2:1 and 1:2.

The coordinates of a point dividing the line segment joining (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) internally in the ratio m : n is \((\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n},\frac{mz_2+nz_1}{m+n})\).

For 1:2, coordinates of point are \((\frac{1*13+2*4}{1+2},\frac{1*27+2*9}{1+2},\frac{-4+2*8}{1+2})\) = (7, 15, 4)

For 2:1, coordinates of point are \((\frac{2*13+1*4}{1+2},\frac{2*27+1*9}{1+2},\frac{-8+1*8}{1+2})\) = (10, 21, 0)

8. Find the points which trisects the line joining (4, 9, 8) and (13, 27, -4).

a) (0, 21, 10)

b) (0, 21, 4)

c) (10, 21, 0)

d) (4, 4, 0)

View Answer

Explanation: Points which trisect the line divides it into 2:1 and 1:2.

The coordinates of a point dividing the line segment joining (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) internally in the ratio m : n is \((\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n},\frac{mz_2+nz_1}{m+n})\).

For 1:2, coordinates of point are \((\frac{1*13+2*4}{1+2},\frac{1*27+2*9}{1+2},\frac{-4+2*8}{1+2})\) = (7, 15, 4)

For 2:1, coordinates of point are \((\frac{2*13+1*4}{1+2},\frac{2*27+1*9}{1+2},\frac{-8+1*8}{1+2})\) = (10, 21, 0)

9. If P (2, 3, 9), Q (2, 5, 5) and R (8, 5, 3) are vertices of a triangle then find the length of median through P.

a) \(\sqrt{24}\)

b) \(\sqrt{38}\)

c) \(\sqrt{11}\)

d) \(\sqrt{53}\)

View Answer

Explanation: We know, midpoint of (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) is ((x

_{1}+x

_{2})/2, (y

_{1}+y

_{2})/2, (z

_{1}+z

_{2})/2).

Midpoint of line QR is (5, 5, 4).

Length of median through P is distance between midpoint of QR and P i.e. \(\sqrt{(5-2)^2+(5-3)^2+(4-9)^2} = \sqrt{(3)^2+(2)^2+(-5)^2} = \sqrt{38}\)

10. If P (2, 3, 9), Q (2, 5, 5) and R (8, 5, 3) are vertices of a triangle then find the length of median through Q.

a) \(\sqrt{24}\)

b) \(\sqrt{38}\)

c) \(\sqrt{11}\)

d) \(\sqrt{53}\)

View Answer

Explanation: We know, midpoint of (x

_{1}, y

_{1}, z

_{1}) and (x

_{2}, y

_{2}, z

_{2}) is ((x

_{1}+x

_{2})/2, (y

_{1}+y

_{2})/2, (z

_{1}+z

_{2})/2).

Midpoint of line PR is (5, 4, 6).

Length of median through Q is distance between midpoint of PR and Q i.e. \(\sqrt{(5-2)^2+(4-5)^2+(6-5)^2} = \sqrt{(3)^2+(-1)^2+(1)^2} = \sqrt{11}\).

**Sanfoundry Global Education & Learning Series – Mathematics – Class 11**.

To practice all areas of Mathematics, __ here is complete set of 1000+ Multiple Choice Questions and Answers__.

**Next Steps:**

- Get Free Certificate of Merit in Mathematics - Class 11
- Participate in Mathematics - Class 11 Certification Contest
- Become a Top Ranker in Mathematics - Class 11
- Take Mathematics - Class 11 Tests
- Chapterwise Practice Tests: Chapter 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
- Chapterwise Mock Tests: Chapter 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

**Related Posts:**

- Practice Class 11 - Chemistry MCQs
- Practice Class 12 - Mathematics MCQs
- Practice Class 11 - Physics MCQs
- Buy Class 11 - Mathematics Books
- Practice Class 11 - Biology MCQs