This set of Mathematics Question Paper focuses on “Graphical Solution of Linear Variable in Two Variables”.
1. The region containing all the solutions of an inequality is called solution region.
a) True
b) False
View Answer
Explanation: When the inequalities are plotted on graph, the region containing all the solutions of an inequality is called the solution region.
2. 2x+y>5. Which of the following will satisfy the given equation?
a) (1,1)
b) (1,2)
c) (2,1)
d) (2,2)
View Answer
Explanation: 2x+y>5
(1,1) x=1 and y=1 gives 2(1)+1>5 =>3>5 which is false.
(1,2) x=1 and y=2 gives 2(1)+2>5 =>4>5 which is false.
(2,1) x=2 and y=1 gives 2(2)+1>5 =>5>5 which is false.
(2,2) x=2 and y=2 gives 2(2)+2>5 =>6>5 which is true.
3. Inequations involved in the given region are____________
a) 2x+y≥6, x≥0, y≥0
b) 2x+y>6, x≥0, y≥0
c) 2x+y<6, x≥0, y≥0
d) 2x+y≤6, x≥0, y≥0
View Answer
Explanation: Since region involves 1st quadrant so x≥0, y≥0.
Two points on line are (0,6) and (3,0).
(y-6)/(0-6) = (x-0)/(3-0)
=>(y-6)/(-6) = x/3
=>y-6=-2x => 2x+y=6
2x+y≤6 since (0,0) should also satisfy.
So, 2x+y≤6, x≥0, y≥0.
4. Inequations involved in the given region are____________
a) 2x+3y>6
b) 2x+3y<6
c) 2x+3y≥6
d) 2x+3y≤6
View Answer
Explanation: (0,2) and (3,0) are two points on line.
(y-2)/(0-2) = (x-0)/(3-0)
=>(y-2)/(-2) = x/3
=>3y-6 = -2x => 2x+3y = 6
Since (0,0) does not satisfy 2x+3y = 6 so, 2x+3y≥6.
5. y<-2 involves region are____________
a) above dotted line y=-2
b) below dotted line y=-2
c) above complete line y=-2
d) below complete line y=-2
View Answer
Explanation: y<-2 does not satisfy (0,0) so, region is below y = -2.
Since only inequality sign given, so dotted line y = -2.

6. 3x-6 ≥0 are____________
a) right side with dotted x=2
b) left side with dotted x=2
c) right side with complete line x=2
d) left side with complete line x=2
View Answer
Explanation: 3x-6 ≥ 0 => x ≥ 2.
(0,0) does not satisfy te equation so region is right side of x=2 with complete line x=2 due to presence of equality sign along with inequality sign.

7. IQ of a person is given by the formula
IQ =(MA/CA) × 100, where MA is mental age and CA is chronological age. If 40 ≤ IQ ≤ 120 for a group of 10 years old children, find the range of their mental age.
a) (9,16)
b) [9,16]
c) (4,12)
d) [4,12]
View Answer
Explanation: IQ =(MA/CA) × 100
=>MA = IQ * CA /100. Given, CA=10 years
40≤ IQ ≤120
=> 40*CA ≤ IQ*CA ≤ 120*CA
=> 40*10 ≤ IQ*CA ≤ 120*10
=> \(\frac{40*10}{100}≤\frac{IQ*CA}{100}≤\frac{120*10}{100}\)
=> 4 ≤ MA ≤ 12.
8. A solution is to be kept between 77° F and 86° F. What is the range in temperature in degree Celsius (C) if the Celsius / Fahrenheit (F) conversion formula is given by F = 9/5 C + 32°?
a) [15°, 20°]
b) [20°, 25°]
c) [25°, 30°]
d) [30°, 35°]
View Answer
Explanation: F = 9/5 C + 32°
C=(F-32°)*5/9
77° ≤ F ≤ 86°
=> 77°-32° ≤ F-32° ≤ 86° -32°
=> 45° ≤ F-32° ≤ 54°
=>45o*5/9 ≤ (F-32°) *5/9 ≤ 54°*5/9
=>25° ≤ C ≤ 30°.
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