Class 10 Maths MCQ – Trigonometric Ratios of Specific Angles – 1

This set of Class 10 Maths Chapter 8 Multiple Choice Questions & Answers (MCQs) focuses on “Trigonometric Ratios of Specific Angles – 1”.

1. What is the value of sec θ when θ is 45°?
a) √3
b) 1
c) 0
d) √2
View Answer

Answer: d
Explanation: The value of cos 45° is \(\frac {1}{\sqrt 2}\) and secant is inverse to cos.
So, sec θ = \(\frac {1}{cos \, \theta } = \frac {1}{1/\sqrt 2}\)
= √2

2. What is the value of sin 0° + cos 0°?
a) 0
b) 2
c) 1
d) ∞
View Answer

Answer: c
Explanation: The value of sin 0° is 0 and the value of cos 0° is 1.
sin 0° + cos 0° = 0 + 1
= 1

3. Evaluate cos 30° sin 60° + cos 60° sin 30°.
a) 2
b) 0
c) 1
d) ∞
View Answer

Answer: c
Explanation: cos 30° sin 60° + cos 60° sin 30° = \(\frac {\sqrt 3}{2} . \frac {\sqrt {3}}{2} + \frac {1}{2} . \frac {1}{2}\)
= \(\frac {3 + 1}{4}\)
= \(\frac {4}{4}\)
= 1
advertisement
advertisement

4. What is the value of cos (30° + 60°)?
a) 1
b) \(\frac {1}{4}\)
c) \(\frac {3}{4}\)
d) 0
View Answer

Answer: a
Explanation: cos (30° + 60°) = cos (90°) = 1
The value of cos (90°) is 1

5. 60° lies in the_____ quadrant.
a) first
b) second
c) third
d) fourth
View Answer

Answer: a
Explanation: A plane is divided into four quadrants. The first quadrant ranges from 0° to 90°. So, 60° lies between 0° to 90° which is in the first quadrant of a plane.
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

6. What is the value of \(\frac {2 cot \, ⁡60^{\circ }}{1 + cot \, ⁡⁡45^{\circ }}\)?
a) Cot 30°
b) Cot 45°
c) Cot 60°
d) Tan 60°
View Answer

Answer: c
Explanation: \(\frac {2 cot \, ⁡⁡60^{\circ }}{1 + cot \, ⁡⁡45^{\circ }} = \frac {2 (\frac {1}{\sqrt 3})}{1 + 1}\)
= \(\frac {\frac {2}{\sqrt {3}}}{2}\)
= \(\frac {1}{\sqrt 3}\)
= Cot 60°

7. Cosec 0° is _____
a) Not defined
b) 1
c) 0
d) 2
View Answer

Answer: a
Explanation: Cosec 0° = \(\frac {1}{Sin \, ⁡0^{\circ } } = \frac {1}{0}\)
Any number divided with 0 is always not defined.
advertisement

8. The value of sin 90° + cos 0° + √2 cos 45° is_____
a) 2
b) 1
c) 4
d) 3
View Answer

Answer: d
Explanation: sin 90° + cos 0° + √2 cos 45° = 1 + 1 + √2 (\(\frac {1}{\sqrt {2}}\))
= 1 + 1 + 1
= 3

9. Cosec 90° is _____
a) 0
b) 2
c) 1
d) √3
View Answer

Answer: c
Explanation: Cosec 90° = \(\frac {1}{Sin \, ⁡90^{\circ } }\)
= \(\frac {1}{1}\)
= 1
advertisement

10. \(\frac {Cos \, ⁡0^{\circ }}{1 – Sin \, ⁡30^{\circ }}\) is _____
a) 1
b) 2
c) 3
d) 4
View Answer

Answer: b
Explanation: \(\frac {Cos \, ⁡0^{\circ }}{1 – Sin \, ⁡30^{\circ }} = \frac {1}{1 – 1/2}\)
= \(\frac {1}{1/2}\)
= 2

Sanfoundry Global Education & Learning Series – Mathematics – Class 10.

To practice all chapters and topics of class 10 Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.