This set of Class 10 Maths Chapter 8 Multiple Choice Questions & Answers (MCQs) focuses on “Trigonometric Ratios of Specific Angles – 2”.
1. What is the value of tan θ when θ is 30°?
a) \( \frac {1}{\sqrt 3}\)
b) 1
c) 0
d) 2
View Answer
Explanation: Tan θ = \( \frac {Sin \, \theta}{Cos \, \theta} = \frac {Sin \, 30^{\circ }}{Cos \, 30^{\circ }} \)
= \( \frac {1/2}{\sqrt 3/2}\)
= \( \frac {1}{2} \times \frac {2}{\sqrt 3}\)
= \( \frac {1}{\sqrt 3}\)
2. What is the value of sec 0° + cosec 90°?
a) 0
b) 2
c) 1
d) ∞
View Answer
Explanation: The value of sec 0° is 1 and the value of cosec 90° is 1.
sec 0° + cosec 90° = 1 + 1
= 2
3. Evaluate sin2 30.
a) 2
b) 0
c) \( \frac {1}{4}\)
d) ∞
View Answer
Explanation: Sin2 30° = (\( \frac {1}{2}\))2
= \( \frac {1}{4}\)
4. What is the value of cos 45° + sin 45°?
a) 1
b) \( \frac {1}{4}\)
c) \( \frac {3}{4}\)
d) √2
View Answer
Explanation: cos 45° + sin 45° = \( \frac {1}{\sqrt 2} + \frac {1}{\sqrt 2}\)
= 2 × \( \frac {1}{\sqrt 2}\) ( Since, 2 = √2 × √2 )
= √2
5. 135° lies in the third quadrant.
a) True
b) False
View Answer
Explanation: A plane is divided into four quadrants. The second quadrant ranges from 90° to 180°. So, 135° lies between 90° to 180° which is in the second quadrant of a plane not in the third quadrant.
6. What is the value of sec 60° – \( \frac {1}{cosec \, 90^{\circ }}\)?
a) Cot 30°
b) Cot 45°
c) Cot 60°
d) Tan 60°
View Answer
Explanation: sec 60° – \( \frac {1}{cosec \, 90^{\circ }}\) = 2 – \( \frac {1}{1}\)
= 1
= cot 45°
7. Tan 90° is _____
a) Not defined
b) 1
c) 0
d) 2
View Answer
Explanation: Tan 90° = \(\frac {Sin \, 90^{\circ }}{Cos \, 90^{\circ }} = \frac {1}{0}\)
Any number divided with 0 is always not defined.
8. The value of sin2 90° + √2 cos 45° + √3 cot 30° is_____
a) 2
b) 0
c) 4
d) 5
View Answer
Explanation: sin2 90° + √2 cos 45° + √3 cot 30° = 12 + √2 (\( \frac {1}{\sqrt 2}\)) + √3 (√3)
= 1 + 1 + 3
= 5
9. The product of sec 30° and cos 60° is _____
a) 0
b) 2
c) 1
d) \( \frac {1}{\sqrt 3}\)
View Answer
Explanation: (sec 30°) (cos 60°) = \(( \frac {2}{\sqrt 3}) ( \frac {1}{2} )\)
= \( \frac {1}{\sqrt 3}\)
10. \( \frac {1 – cot \, 45^{\circ}}{1+ cot \, 45^{\circ}}\) is _____
a) 0
b) 2
c) 3
d) 1
View Answer
Explanation: \( \frac {1 – cot \, 45^{\circ}}{1 + cot \, 45^{\circ}} = \frac {1-1}{1+1}\)
= \( \frac {0}{1}\)
= 0
Sanfoundry Global Education & Learning Series – Mathematics – Class 10.
To practice all chapters and topics of class 10 Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.
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- Practice Class 9 Mathematics MCQs
- Practice Class 8 Mathematics MCQs
- Check Class 10 - Mathematics Books
