This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Statistics – Median of Grouped Data”.

1. What is the median?

a) Difference between higher half and lower half of the data set

b) Mean of the highest and lowest number in a data sample

c) Value separating higher half from the lower half of a data sample

d) Difference between the highest and lowest number.

View Answer

Explanation: In statistics, the Median is also called the ‘Middle Value’ as it is the value that separates the Highest half from the lower half of a data sample.

2. What is the Median of the following data sample?

2, 7, 4, 8, 9, 10, 6, 12, 13

a) 8

b) 11

c) 9

d) 10

View Answer

Explanation: Arranging the data sample in ascending order 2, 4, 6, 7, 8, 9, 10, 12, 13.

Median is the middle value which separates the higher half from the lower half in a data sample. After arranging them in ascending order, 8 is the Middle value.

3. What is the Median of the following data sample?

3, 7, 4, 8, 9, 6, 10, 12, 13, 15

a) 7.5

b) 9

c) 8.5

d) 10

View Answer

Explanation: Arranging the data set in ascending order 3, 4, 6, 7, 8, 9, 10, 12, 13, 15

8 and 9 are the two middle numbers.

Median is the mean of the middle two numbers.

Median is the mean of the middle two numbers = \(\frac {8+9}{2}\) = 8.5

4. Some of the samples are given below. Find the median.

90, 45, 67, 34, 26, 76, 44, 55.

a) 55

b) 45

c) 40

d) 50

View Answer

Explanation: There is an even number of terms in this Data Set. So, the median will be the mean of the middle two numbers.

Arranging them in ascending order 26, 34, 44, 45, 55, 67, 76, 90.

45 and 55 are the middle two numbers. So, Median = \(\frac {45+55}{2}\) = 50

5. If the mean and the mode are given as 35 and 30. Find the Median.

a) 75

b) 33.33

c) 19

d) 32

View Answer

Explanation: The empirical mean median mode relation is given as

Mean – Mode = 3(Mean – Median)

Given Mean = 35, Mode = 30

35 – 30 = 3(35 – Median )

5 = 105 – 3 Median

Median = 33.33

6. If the Mean and Mode are 25, then find the Median.

a) 13

b) 9

c) 25

d) 0

View Answer

Explanation: The empirical mean median mode relation is given as

Mean – Mode = 3(Mean – Median)

25 – 25 = 3(25 – Median )

Median = 25

7. What is the formula for the median of Grouped data?

a) Median = L + [(n / 2 – cf) / f] * h

b) Median = L + [(n / 2 + cf) / f] * h

c) Median = L + [(n / 2 – cf) / f] + h

d) Median = L * [(n / 2 – cf) / f] * h

View Answer

Explanation: Formula for the Median of Grouped Data

Median = L + [(n / 2 – c.f) / f] * h

L = Lower limit of Median Class

cf = Cumulative frequency of the class prior to median class

f = Frequency of Median Class

h = Class size

n = Total frequency

8. Find the Median of the following grouped data.

Marks | Frequency |

0-10 | 9 |

10-20 | 10 |

20-30 | 24 |

30-40 | 16 |

40-50 | 11 |

a) 15

b) 20

c) 26.66

d) 35

View Answer

Explanation: Total frequency n = 9 + 10 + 24 + 16 + 11 = 70

\(\frac {n}{2} = \frac {70}{2}\) = 35

Marks | Frequency | Cumulative Frequency |

0-10 | 9 | 9 |

10-20 | 10 | 9 + 10 = 19 |

20-30 | 24 | 19 + 24 = 43 |

30-40 | 16 | 43 + 16 = 59 |

40-50 | 11 | 59 + 11 = 70 |

35 is less than 43 and greater than 19

So, 20 – 30 is the Median Class

Now L = 20, h = 10, cf = 19, f = 24

Median = L + [(n / 2 – c.f) / f] * h

= 20 + [(35 – 19) / 24] * 10

= 26.66

9. Find the Median of given Grouped data.

Rating | Frequency |

0-5 | 12 |

5-10 | 20 |

10-15 | 10 |

15-20 | 6 |

a) 10

b) 18

c) 8

d) 17.5

View Answer

Explanation: Total Frequency = 12 + 20 + 10 + 6 = 48 and \(\frac {n}{2} = \frac {48}{2}\) = 24

Rating | Frequency | Cumulative Frequency |

0-5 | 12 | 12 |

5-10 | 20 | 20 + 12 = 32 |

10-15 | 10 | 32 + 10 = 42 |

15-20 | 6 | 42 + 6 = 48 |

24 is less than 32 and greater than 12. So, the Median Class is 5 – 10.

L = 5, h = 5, cf = 12, f = 20

Median = L + [(n / 2 – c.f) / f] * h

= 5 + [(24 – 12) / 20] * 5

= 8

10. Find the Median of the following grouped data.

Results | Frequency |

0-20 | 5 |

20-40 | 10 |

40-60 | 30 |

60-80 | 15 |

a) 52

b) 50

c) 34

d) 45

View Answer

Explanation: Total Frequency n = 5 + 10 + 30 + 15 = 60 and \(\frac {n}{2} = \frac {60}{2}\) = 30

Results | Frequency | Cumulative Frequency |

0-20 | 5 | 5 |

20-40 | 10 | 5 + 10 = 15 |

40-60 | 30 | 15 + 30 = 45 |

60-80 | 15 | 45 + 15 = 60 |

30 is less than 45 and greater than 15. So, the median class is 40 – 60.

L = 40, h = 20, cf = 15, f = 30

Median = L + [(n / 2 – c.f) / f] * h

= 40 + [(30 – 15) / 30] * 20

= 50

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