# Chemical Process Calculation Questions and Answers – Stoichiometry – V

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This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Stoichiometry – V”.

1-10. For the given combustion reaction
a C4H10 + b O2 → c CO2 + d H2O
1. What is the value of a?
a) 1
b) 4
c) 5
d) 6.5

Explanation: Carbon and Oxygen on both the sides.

2. What is the value of b?
a) 1
b) 4
c) 5
d) 6.5

Explanation: Carbon and Oxygen on both the sides.

3. What is the value of c?
a) 1
b) 4
c) 5
d) 6.5

Explanation: Carbon and Oxygen on both the sides.

4. What is the value of d?
a) 1
b) 4
c) 5
d) 6.5

Explanation: Carbon and Oxygen on both the sides.

5. For producing 10 moles of H2O, how many moles of C4H10 are required? (Consider O2 is in excess)
a) 1
b) 2
c) 5
d) 10

Explanation: 1 mole of C4H10 is equivalent to 2 moles of H2O.

6. How many moles of O2 are required for producing 10 moles of H2O? (Consider C4H10 is in excess)
a) 6.5
b) 13
c) 15
d) 30

Explanation: 6.5 mole of O2 is equivalent to 5 moles of H2O.

7. How much CO2 in kg can be produced with 1 mole of C4H10? (Consider O2 is in excess)
a) 44
b) 88
c) 132
d) 176

Explanation: 1 mole of C4H10 is equivalent to 4 moles of CO2.

8. How much CO2 in kg can be produced with 1 mole of O2? (Consider C4H10 is in excess)
a) 26.07
b) 27.07
c) 28.08
d) 29.08

Explanation: 6.5 moles of O2 is equivalent to 4 moles of CO2.

9. For producing 90 gms of water in the reaction, how many moles of C4H10 are required?
a) 1
b) 2
c) 3
d) 4

Explanation: 1 mole of C4H10 is equivalent to 5 moles (90 gms) of H2O.

10. For producing 90 gms of water in the reaction, how many moles of O2 are required?
a) 2.5
b) 4.5
c) 6.5
d) 8.5 