# Chemical Process Calculation Questions and Answers – Stoichiometry-II

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This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Stoichiometry-II”.

1-4. For the given following reaction
a NH3 + b O2 → c NO2 + d H2O
1. The value of a, is?
a) 2
b) 4
c) 6
d) 8

Explanation: Balance N, O and H.

2. The value of b, is?
a) 1.5
b) 2.5
c) 3.5
d) 4.5

Explanation: Balance N, O and H.

3. The value of c, is?
a) 2
b) 4
c) 6
d) 8

Explanation: Balance N, O and H.

4. The value of d, is?
a) 1
b) 2
c) 3
d) 4

Explanation: Balance N, O and H.

5. If 1 kg of Octane is oxidised with O2, then how much kg of O2 is required?
a) 200
b) 400
c) 600
d) 800

Explanation: 1 mole of Octane = 12.5 moles of O2.

6. If 1 kg of butane is burned with O2, then how much kg of CO2 will produce by 40 kg of butane?
a) 111.38
b) 121.38
c) 131.38
d) 141.38

Explanation: 1 mole of butane = 4 moles of CO2.

7-8. For the given chemical reaction
C6H14 + 19/2 O2 → 6 CO2+ 7 H2O
7. If the required amount of CO2 is 440 kg/hour then how much kg of C6H14 should be burned per hour?
a) 123.33
b) 143.33
c) 163.33
d) 183.33

Explanation: 1 mole of C6H14 = 6 moles of CO2.

8. If the required amount of water is 72 kg then how much C6H14 should be burned per hour?
a) 49.14
b) 39.14
c) 39.14
d) 29.14

Explanation: 1 mole of C6H14 = 7 moles of H2O.

9-10. For a given chemical reaction
N2 + 3H2 → 2NH3
9. For producing 34 gms of NH3, how many moles of N2 is required?
a) 1
b) 2
c) 3
d) 4

Explanation: 1 mole of N2 = 2 moles of NH3.

10. For producing 34 gms of NH3, how many gms of H2 is required?
a) 3
b) 6
c) 9
d) 12 