This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Element Material Balances”.
1. In a hydro-cracking process, the mole percent of products C4H10, C3H8, and C2H6 are 20.2%, 58.4%, and 21.4%, respectively. What is the mole percent of C6H14 in the feed?
a) 40.2
b) 50.2
c) 60.2
d) 70.2
View Answer
Explanation: The mole percent of C6H14 is determined using element material balance calculations, considering the mole distribution of the products.
2. What is the mole percent of H2 in the feed for a hydro-cracking process, if the mole percent of products C4H10, C3H8, and C2H6 are 20.2%, 58.4%, and 21.4%, respectively?
a) 59.2
b) 49.2
c) 39.2
d) 29.9
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Explanation: The mole percent of H2 in the feed is calculated by performing an element material balance on hydrogen across the entire process.
3. What is the molar ratio of H2 consumed to Hexane (C6H14) reacted in the hydro-cracking process?
a) 1.2
b) 1.4
c) 1.6
d) 1.8
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Explanation: The molar ratio of H2 consumed to Hexane reacted is derived using material balance for hydrogen and carbon in the process, based on the stoichiometry of the reaction.
4. In a reactor producing 40% Methane, 20% Ethane, and 40% Butane, with a feed of Pentane and Hydrogen, what is the mole fraction of Hydrogen in the feed?
a) 0.284
b) 0.484
c) 0.684
d) 0.884
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Explanation: The mole fraction of Hydrogen is determined based on the element material balance for hydrogen. By considering the total moles of hydrogen and the moles of other substances in the feed, the mole fraction is calculated.
5. In a reactor producing 40% Methane, 20% Ethane, and 40% Butane, with a feed of Pentane and Hydrogen, what is the mole fraction of Pentane in the feed?
a) 0.315
b) 0.215
c) 0.115
d) None of the mentioned
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Explanation: The mole fraction of Pentane is calculated using the element material balance for carbon, considering the distribution of moles of methane, ethane, and butane in the feed.
6. In a reactor producing 40% Methane, 20% Ethane, and 40% Butane, with a feed of Pentane and Hydrogen, what is the ratio of Hydrogen to Pentane in the feed?
a) 1.167
b) 2.167
c) 3.167
d) 4.167
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Explanation: The ratio of Hydrogen to Pentane is determined by comparing the moles of hydrogen and pentane in the feed. This ratio is calculated as 104/48, resulting in a ratio of 2.167.
7. When 40 moles of C3H8 is burned in air with 100 moles, what is the number of moles of CO2 in the product?
a) 12.6
b) 10.6
c) 8.6
d) 4.6
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Explanation: Moles of CO2 are calculated as 3 times the extent of the reaction, given the stoichiometry of the combustion reaction of C3H8.
8. When 40 moles of C3H8 is burned in air with 100 moles, what is the number of moles of H2O in the product?
a) 4.8
b) 8.8
c) 16.8
d) 32.8
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Explanation: Moles of H2O are calculated as 2 times the extent of the reaction, based on the stoichiometric combustion of C3H8.
9. When 40 moles of C3H8 is burned in air with 100 moles, what is the number of moles of C3H8 in the product?
a) 25.8
b) 35.8
c) 45.8
d) 55.8
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Explanation: The moles of C3H8 remaining in the product is calculated as the initial moles minus the extent of the reaction.
10. How many moles of O2 are required for the complete combustion of C3H8?
a) 160.48
b) 170.48
c) 180.48
d) 190.48
View Answer
Explanation: The moles of O2 required for the complete combustion of C3H8 are determined by the stoichiometric combustion reaction, considering that each mole of C3H8 requires a certain number of moles of O2.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
To practice all areas of Chemical Process Calculation, here is complete set of 1000+ Multiple Choice Questions and Answers.
