This set of Basic Chemical Process Calculation questions and answers focuses on “Ideal Gases – III”.
1. If a gas is heated at constant volume, which of the following statements is true?
a) Kinetic energy of the gas particles will decrease
b) Pressure will increase
c) Number of moles of gas will increase
d) Volume will increase
View Answer
Explanation: P is inversely proportional to temperature and the volume is constant (PV = nRT). Moles of the gas are constant.
2. If the volume of a gas doubled at constant temperature, what is the pressure now if it was P atm before the change?
a) P atm
b) 2P atm
c) P/2 atm
d) None of the mentioned
View Answer
Explanation: P is inversely proportional to temperature and the volume is constant (PV = nRT).
3. What is the pressure of 2 moles of gas that is heated at 27 degree Celsius. Volume and gas constant ration for the gas is 4.
a) 150 N/m2
b) 300 N/m2
c) 600 N/m2
d) 800 N/m2
View Answer
Explanation: PV = nRT
4. Volumetric flow rate for a given gas can be expressed in cubic feet per second.
The above given statement is
a) Correct
b) Incorrect
c) Depends on the nature of the gas
d) None of the mentioned
View Answer
Explanation: For volumetric flow rate we divide the volume by time that is passing through a pipe.
5. For 5 moles of an ideal gas,
Condition I: Pressure = 1 atm, Volume = 2 L, Temperature = 27 Degree Celsius
Condition II: Pressure = P atm, Volume = V L, Temperature = T K.
5. If The Pressure and Volume in the II condition are 2 atm and 4 L, what is the temperature (T) of the gas?
a) 300 K
b) 600 K
c) 900 K
d) 1200 K
View Answer
Explanation: (P1V1/T1) = (P2V2/T2).
6. If the Pressure and Temperature in the II condition are 2 atm and 600K, what is the volume (V) of the gas?
a) 2 L
b) 4 L
c) 6 L
d) 8 L
View Answer
Explanation: (P1V1/T1) = (P2V2/T2).
7. If the Temperature and the pressure of the gas in the II condition are 1000 K and 8 atm, what is the temperature of the gas?
a) 1 atm
b) 2 atm
c) 4 atm
d) 8 atm
View Answer
Explanation: (P1V1/T1) = (P2V2/T2).
8. What is the density of an ideal gas at 4 KPa pressure having a molecular wt. of 28 gms ? If the PV value for 1 mole of gas is 8000 (Pa)(cm3).
a) 14 g/cm3
b) 28 g/cm3
c) 44 g/cm3
d) 88 g/cm3
View Answer
Explanation: ρ = PM/RT and PV = nRT.
9-10. For Oxygen gas (assume ideal), 5 gm moles of the gas is heated at 200 K temperature and 5 atm pressure.
9. What is the volume of the gas?
a) 16.4 m3
b) 38.4 m3
c) 44.5 m3
d) 85.6 m3
View Answer
Explanation: PV = nRT.
10. If the temperature and pressure both are made doubled then what is the volume of the gas?
a) 16.4 m3
b) 38.4 m3
c) 44.5 m3
d) 85.6 m3
View Answer
Explanation: PV = nRT, P` = 2P and T` = 2T, then P`V = nRT` & that is equal to PV = nRT.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
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