This set of Basic Chemical Process Calculation questions and answers focuses on “Ideal Gases – III”.
1. If a gas is heated at constant volume, which of the following statements is true?
a) Kinetic energy of the gas particles will decrease
b) Pressure will increase
c) Number of moles of gas will increase
d) Volume will increase
View Answer
Explanation: P is inversely proportional to temperature and the volume is constant (PV = nRT). Moles of the gas are constant.
2. If the volume of a gas doubled at constant temperature, what is the pressure now if it was P atm before the change?
a) P atm
b) 2P atm
c) P/2 atm
d) None of the mentioned
View Answer
Explanation: P is inversely proportional to temperature and the volume is constant (PV = nRT).
3. What is the pressure of 2 moles of gas that is heated at 27 degree Celsius. Volume and gas constant ration for the gas is 4.
a) 150 N/m2
b) 300 N/m2
c) 600 N/m2
d) 800 N/m2
View Answer
Explanation: PV = nRT
4. Volumetric flow rate for a given gas can be expressed in cubic feet per second.
The above given statement is
a) Correct
b) Incorrect
c) Depends on the nature of the gas
d) None of the mentioned
View Answer
Explanation: For volumetric flow rate we divide the volume by time that is passing through a pipe.
5. For 5 moles of an ideal gas at an initial state of 1 atm, 2 L, and 27°C, if the pressure and volume in a new condition are 2 atm and 4 L respectively, what is the temperature T of the gas?
a) 300 K
b) 600 K
c) 900 K
d) 1200 K
View Answer
Explanation: (P1V1/T1) = (P2V2/T2).
6. Given 5 moles of an ideal gas initially at 1 atm, 2 L, and 27°C, if the pressure and temperature in a new condition are 2 atm and 600 K respectively, what is the volume V of the gas?
a) 2 L
b) 4 L
c) 6 L
d) 8 L
View Answer
Explanation: (P1V1/T1) = (P2V2/T2).
7. If 5 moles of an ideal gas initially have a pressure of 1 atm, volume of 2 L, and temperature of 27°C, and the temperature and pressure of the gas in a new condition are set to 1000 K and 8 atm, respectively, what is the volume of the gas?
a) 1 atm
b) 2 atm
c) 4 atm
d) 8 atm
View Answer
Explanation: (P1V1/T1) = (P2V2/T2).
8. What is the density of an ideal gas at 4 KPa pressure having a molecular wt. of 28 gms ? If the PV value for 1 mole of gas is 8000 (Pa)(cm3).
a) 14 g/cm3
b) 28 g/cm3
c) 44 g/cm3
d) 88 g/cm3
View Answer
Explanation: ρ = PM/RT and PV = nRT.
9. For 5 moles of oxygen gas (ideal) at 200 K and 5 atm pressure, what is the volume of the gas?
a) 16.4 m3
b) 38.4 m3
c) 44.5 m3
d) 85.6 m3
View Answer
Explanation: PV = nRT.
10. If for 5 moles of oxygen gas initially at 200 K and 5 atm pressure, both the temperature and pressure are doubled, what is the resulting volume of the gas?
a) 16.4 m3
b) 38.4 m3
c) 44.5 m3
d) 85.6 m3
View Answer
Explanation: PV = nRT, P` = 2P and T` = 2T, then P`V = nRT` & that is equal to PV = nRT.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
To practice basic questions on all areas of Chemical Process Calculation, here is complete set of 1000+ Multiple Choice Questions and Answers.
