This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Stoichiometry- VIII”.
1. In the reaction CH4 + Cl2 → CH3Cl + HCl, how many moles of CH4 are required to produce 1 mole of CH3Cl?
a) 1
b) 4
c) 5
d) 6.5
View Answer
Explanation: The stoichiometry of the reaction shows that 1 mole of CH4 produces 1 mole of CH3Cl.
2. For the reaction CH4 + Cl2 → CH3Cl + HCl, how many moles of Cl2 are required to produce 1 mole of CH3Cl?
a) 1
b) 4
c) 5
d) 6.5
View Answer
Explanation: The reaction shows that 1 mole of Cl2 is required to produce 1 mole of CH3Cl.
3. How many moles of CH4 are required to produce 1 mole of HCl in the reaction CH4 + Cl2 → CH3Cl + HCl?
a) 1
b) 4
c) 5
d) 6.5
View Answer
Explanation: According to the stoichiometry, 1 mole of CH4 produces 1 mole of HCl.
4. In the reaction CH4 + Cl2 → CH3Cl + HCl, how many moles of Cl2 are needed to produce 1 mole of HCl?
a) 1
b) 4
c) 5
d) 6.5
View Answer
Explanation: The stoichiometry shows that 1 mole of Cl2 produces 1 mole of HCl.
5. If the amount of CH4 is doubled in the reaction CH4 + Cl2 → CH3Cl + HCl, what will happen to the number of moles of CH3Cl formed, assuming Cl2 is in excess?
a) Doubled
b) Half
c) Four times
d) None of the mentioned
View Answer
Explanation: With Cl2 in excess, doubling CH4 doubles the moles of CH3Cl formed due to a 1:1 molar ratio.
6. In the reaction CH4 + Cl2 → CH3Cl + HCl, if the amount of CH4 is doubled and Cl2 is in excess, what happens to the number of moles of HCl formed?
a) Doubled
b) Half
c) Four times
d) None of the mentioned
View Answer
Explanation: Since each mole of CH4 produces 1 mole of HCl, doubling CH4 doubles the moles of HCl formed.
7. Given the molecular weight of Cl2 is 71 g/mol, how many moles of CH3Cl can be produced with 71 grams of Cl2, assuming CH4 is in excess?
a) 1
b) 2
c) 3
d) None of the mentioned
View Answer
Explanation: 71 grams of Cl2 is equivalent to 2 moles, producing 2 moles of CH3Cl.
8. In the reaction CH4 + Cl2 → CH3Cl + HCl, how many moles of HCl can be produced from 71 grams of Cl2, assuming CH4 is in excess?
a) 1
b) 2
c) 3
d) None of the mentioned
View Answer
Explanation: Since 71 grams of Cl2 is 2 moles, it can produce 2 moles of HCl.
9. If 16 grams of CH4 are available, how many grams of CH3Cl can be produced, given Cl2 is in excess? (Molecular weights: CH4 = 16 g/mol, CH3Cl = 50.5 g/mol)
a) 50.5
b) 58.5
c) 60.5
d) None of the mentioned
View Answer
Explanation: 16 grams of CH4 is 1 mole, which produces 1 mole (50.5 grams) of CH3Cl.
10. In the reaction CH4 + Cl2 → CH3Cl + HCl, if 16 grams of CH4 are used, how many grams of HCl will be produced, given Cl2 is in excess? (Molecular weights: CH4 = 16 g/mol, HCl = 36.5 g/mol)
a) 18.5
b) 36.5
c) 54.5
d) None of the mentioned
View Answer
Explanation: 1 mole of CH4 (16 grams) produces 1 mole of HCl, which is 36.5 grams.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
To practice all areas of Chemical Process Calculation, here is complete set of 1000+ Multiple Choice Questions and Answers.
