This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Mole and Molecular Weight-I”.
1. Amount of substance containing 6.022*10^23 entities is called
a) Mole
b) Molecular weight
c) Molar mass
d) None of the mentioned
View Answer
Explanation: Amount of substance containing 6.022*10^23 entities is called mole.
2. Two statements are given as below
I: lb mole is composed of 453.6*6.022*1023 molecules
II: gm mole is composed of 6.022*1023 molecules
Number of correct statements is/are
a) 0
b) 1
c) 2
d) None of the mentioned
View Answer
Explanation: A gm mole is composed of 6.022*10^23 molecules and 1 lb mole is 453.6 times a gm mole.
3. Molecular weight is the ratio of _______ and ________
a) Mass, Mole
b) Mole, Mass
c) Mole, Mole
d) Mass, Mass
View Answer
Explanation: Molecular weight is the ratio of Mass and Mole.
4. How many g moles of H are there in 22 g of H2SO4?
a) 0.4489
b) 0.2245
c) 0.1256
d) 0.3256
View Answer
Explanation: g moles of H = 2(gm moles of H2SO4).
5. How many g moles of S are there in 22 g of H2SO4?
a) 0.4489
b) 0.2245
c) 0.1256
d) 0.3256
View Answer
Explanation: g moles of S = gm moles of H2SO4.
6. How many lb moles of O are there in 22 g of H2SO4?
a) 1.978*10-4
b) 1.978*10-3
c) 1.978*10-2
d) 1.978*10-1
View Answer
Explanation: lb mole = 454*gm mole, lb moles of O = 4(lb moles of H2SO4).
7-8. 500 lb of N2 is there in a container
7. How many pound moles of N2 does it contain?
a) 17.86
b) 35.7
c) 0.039
d) 0.078
View Answer
Explanation: lb moles = mass in lb/molecular weight.
8. How many gram moles of N2 does it contain?
a) 8107
b) 6789
c) 7583
d) 7357
View Answer
Explanation: gm moles = mass in gm/molecular weight.
9. 58.5 gms of NaCl contains
a) 1 gm mole of NaCl
b) 1 lb mole of NaCl
c) Both a and b
d) Neither a nor b
View Answer
Explanation: gm moles = mass in gm/molecular weight.
10.40 gms of NaOH contains
a) 6.022*1023 molecules
b) 1 molecule
c) 13.24*1021 molecules
d) 6.022*1021 molecules
View Answer
Explanation: 40 gms of NaOH = 1 gm mole of NaOH = 6.022*10^23 molecules.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
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