This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Mole and Molecular Weight-IV”.
1. How many moles of NaOH are there in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4? (Molecular weight of NaOH is 40)
a) 1.0
b) 1.2
c) 1.4
d) 1.6
View Answer
Explanation: Number of moles = mass / molecular weight = 48 / 40 = 1.2.
2. How many moles of H2SO4 are there in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4? (Molecular weight of H2SO4 is 98)
a) 1.44
b) 1.88
c) 2.44
d) 2.88
View Answer
Explanation: Number of moles = mass / molecular weight = 184 / 98 ≈ 1.88.
3. How many moles of H2O are there in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4? (Molecular weight of H2O is 18)
a) 3.1
b) 3.2
c) 3.3
d) 3.4
View Answer
Explanation: Number of moles = mass / molecular weight = 56 / 18 ≈ 3.1.
4. What is the number of moles of Oxygen present in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4?
a) 14.82
b) 13.82
c) 12.82
d) 11.82
View Answer
Explanation: Moles of Oxygen = Moles of NaOH + Moles of H2O + 4(Moles of H2SO4).
5. How many moles of Hydrogen are there in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4?
a) 11.00
b) 11.16
c) 11.56
d) 11.98
View Answer
Explanation: Moles of Hydrogen = Moles of NaOH + 2(Moles of H2O) + 2(Moles of H2SO4).
6. What is the weight percentage of H2O in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4?
a) 19.44
b) 14.42
c) 12.56
d) 10.28
View Answer
Explanation: Weight percentage = (mass of H2O / Total mass) × 100 = (56 / 288) × 100 ≈ 19.44.
7. What is the mole percentage of H2SO4 in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4?
a) 10.4
b) 20.4
c) 30.4
d) 40.4
View Answer
Explanation: Mole percentage = (moles of H2SO4 / Total moles) × 100.
8. What is the weight percentage of NaOH in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4?
a) 14.67
b) 15.67
c) 16.67
d) 17.67
View Answer
Explanation: Weight percentage = (mass of NaOH / Total mass) × 100 = (48 / 288) × 100 ≈ 16.67.
9. What is the mole percentage of NaOH in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4?
a) 20.4
b) 19.4
c) 18.4
d) 17.4
View Answer
Explanation: Mole percentage = (moles of NaOH / Total moles) × 100.
10. What is the weight percentage of H2SO4 in the bucket containing 48 g of NaOH, 56 g of H2O, and 184 g of H2SO4?
a) 14.82
b) 25.69
c) 58.67
d) 63.88
View Answer
Explanation: Weight percentage = (mass of H2SO4 / Total mass) × 100 = (184 / 288) × 100 ≈ 63.88.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
To practice all areas of Chemical Process Calculation, here is complete set of 1000+ Multiple Choice Questions and Answers.
