This set of Chemical Process Calculation Multiple Choice Questions & Answers (MCQs) focuses on “Stoichiometry-I”.
1. The given statement for stoichiometry is
“Stoichiometry provides a quantitative means of relating the amount of products produced by a chemical reaction to amount of reaction and vice versa.”
a) True
b) False
c) Insufficient information to predict
d) None of the mentioned
View Answer
Explanation: The above given statement is a correct definition of stoichiometry.
2. The law of _____________ states that chemical reactions proceed with fix ratios of the number of reactant and products and products involved in the reaction.
a) Mass Conservation
b) Mole Conservation
c) Constant Proportionality
d) None of the mentioned
View Answer
Explanation: The law of constant proportionality states that chemical reactions proceed with fix ratios of the number of reactant and products and products involved in the reaction.
3. For the combustion reaction of glucose C6H12O6 + a O2 → b CO2 + c H2O, what is the value of a (the coefficient for O2) when the reaction is balanced?
a) 2
b) 4
c) 6
d) 8
View Answer
Explanation: Balancing the reaction requires 6 molecules of O2 to match the oxygen atoms on both sides.
4. In the balanced combustion reaction of glucose C6H12O6 + a O2 → b CO2 + c H2O, what is the value of b (the coefficient for CO2)?
a) 2
b) 4
c) 6
d) 8
View Answer
Explanation: Balancing carbon atoms shows that 6 molecules of CO2 are produced from 6 carbon atoms in glucose.
5. In the balanced combustion reaction of glucose C6H12O6 + a O2 → b CO2 + c H2O, what is the value of c (the coefficient for H2O)?
a) 2
b) 4
c) 6
d) 8
View Answer
Explanation: Balancing hydrogen atoms requires 6 molecules of H2O to match the 12 hydrogen atoms in glucose.
6. For the balanced combustion reaction of glucose C6H12O6 + 6 O2 → 6 CO2 + 6 H2O, if 360 grams of glucose is available, how many grams of O2 are required?
a) 124
b) 284
c) 308
d) 384
View Answer
Explanation: 1 mole of glucose (180 g) requires 6 moles of O2 (192 g). Therefore, 360 g of glucose requires 2 × 192 = 384 g of O2.
7. In the combustion reaction of glucose C6H12O6 + 6 O2 → 6 CO2 + 6 H2O, how many kilograms of glucose are required to produce 6 moles of H2O?
a) 180
b) 360
c) 540
d) 720
View Answer
Explanation: 1 mole of glucose produces 6 moles of H2O. The molar mass of glucose is 180 g (0.18 kg).
8. If 44 grams of CO2 is produced in the combustion reaction C6H12O6 + 6 O2 → 6 CO2 + 6 H2O, how many kilograms of glucose were in the feed?
a) 30
b) 60
c) 90
d) 120
View Answer
Explanation: 1 mole of glucose (180 g) produces 6 moles of CO2 (264 g), so 44 g of CO2 corresponds to 44/264 × 180 = 30 kg of glucose.
9. In the combustion reaction C6H12O6 + 6 O2 → 6 CO2 + 6 H2O, if 360 grams of glucose is burned, how many grams of CO2 will be produced?
a) 228
b) 328
c) 428
d) 528
View Answer
Explanation: 1 mole of glucose (180 g) produces 6 moles of CO2 (264 g). So, 360 g of glucose produces 2 × 264 = 528 g of CO2.
10. In the reaction C6H12O6 + 6 O2 → 6 CO2 + 6 H2O, if 64 grams of O2 is available, how many grams of H2O can be produced?
a) 18
b) 36
c) 54
d) 72
View Answer
Explanation: 1 mole of O2 (32 g) produces 1 mole of H2O (18 g). Therefore, 64 g of O2 produces 64/32 × 18 = 36 g of H2O.
Sanfoundry Global Education & Learning Series – Chemical Process Calculation.
To practice all areas of Chemical Process Calculation, here is complete set of 1000+ Multiple Choice Questions and Answers.
