Signals & Systems Questions and Answers – Eigenvalues

This set of Signals & Systems Multiple Choice Questions & Answers (MCQs) focuses on “Eigenvalues”.

1. Find the Eigen values of matrix \(A = \begin{bmatrix}
2 & 1 & 0\\
1 & 2 & 1\\
0 & 1 & 2\\
\end{bmatrix}\).
a) 2 + \(\sqrt{2}\), 2-\(\sqrt{2}\), 2
b) 2, 1, 2
c) 2, 2, 0
d) 2, 2, 2
View Answer

Answer: a
Explanation: To find the Eigen values it satisfy the condition, |A-λI|=0
|A-λI| = \(\begin{bmatrix}
2 & 1 & 0\\
1 & 2 & 1\\
0 & 1 & 2\\
\end{bmatrix} – λ\begin{bmatrix}
1 & 0 & 0\\
0 & 1 & 0\\
0 & 0 & 1\\
\end{bmatrix}\)
|A-λI| = \(\begin{vmatrix}
2-λ & 1 & 0\\
1 & 2-λ & 1\\
0 & 1 & 2-λ\\
\end{vmatrix}\)
= 2 – (λ2-4λ+3) – (2-λ)
By solving the above equation, we get,
λ = 2 + \(\sqrt{2}\), 2-\(\sqrt{2}\), 2.

2. Find the product of Eigen values of a matrix \(A = \begin{bmatrix}
1 & 2 & 4\\
0 & 6 & 0\\
3 & 1 & 2\\
\end{bmatrix}\).
a) 60
b) 45
c) -60
d) 40
View Answer

Answer: c
Explanation: According to the property of Eigen values, the product of the Eigen values of a given matrix is equal to the determinant of the matrix |A| = 1(12-0) – 2(0) + 4(8)
= -60.

3. Let us consider a square matrix A of order n with Eigen values of a, b, c then the Eigen values of the matrix AT could be.
a) a, b, c
b) -a, -b, -c
c) a-b, b-a, c-a
d) a-1, b-1, c-1
View Answer

Answer: a
Explanation: According to the property of the Eigen values, any square matrix A and its transpose AT have the same Eigen values.
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4. What is Eigen value?
a) A vector obtained from the coordinates
b) A matrix determined from the algebraic equations
c) A scalar associated with a given linear transformation
d) It is the inverse of the transform
View Answer

Answer: c
Explanation: Eigen values is a scalar associated with a given linear transformation of a vector space and having the property that there is some nonzero vector which is when multiplied by the scalar is equal to the vector obtained by letting the transformation operate on the vector.

5. Find the sum of the Eigen values of the matrix \(A = \begin{bmatrix}
3 & 6 & 7\\
5 & 4 & 2\\
7 & 9 & 1\\
\end{bmatrix}\).
a) 7
b) 8
c) 9
d) 10
View Answer

Answer: b
Explanation: According to the property of the Eigen values, the sum of the Eigen values of a matrix is its trace that is the sum of the elements of the principal diagonal.
Therefore, the sum of the Eigen values = 3 + 4 + 1 = 8.
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6. Let the matrix A be the idempotent matrix then the Eigen values of the idempotent matrix are ________
a) 0, 1
b) 0
c) 1
d) -1
View Answer

Answer: a
Explanation: According to the property of the Eigen values, the Eigen values of the idempotent matrix are either zero or unity.
So, the answer is 0 or 1.

7. Let us consider a 3×3 matrix A with Eigen values of λ1, λ2, λ3 and the Eigen values of A-1 are?
a) λ1, λ2, λ3
b) \( \frac{1}{λ_1}, \frac{1}{λ_2}, \frac{1}{λ_3}\)
c) -λ1, -λ2, -λ3
d) λ1, 0, 0
View Answer

Answer: b
Explanation: According to the property of the Eigen values, if is the Eigen value of A, then \( \frac{1}{λ}\) is the Eigen value of A-1.
So the Eigen values of A-1 are \( \frac{1}{λ_1}, \frac{1}{λ_2}, \frac{1}{λ_3}\).
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8. The Eigen values of a 3×3 matrix are λ1, λ2, λ3 then the Eigen values of a matrix A3 are __________
a) λ1, λ2, λ3
b) \( \frac{1}{λ_1}, \frac{1}{λ_2}, \frac{1}{λ_3}\)
c) \(λ_1^3, λ_2^3, λ_3^3\)
d) 1, 1, 1
View Answer

Answer: c
Explanation: If λ1, λ2, λ3……… λn are the Eigen values of matrix A then the Eigen values of matrix Am are said to be \(λ_1^m, λ_2^m, λ_3^m,………λ_n^m\).
So, the answer is \(λ_1^3, λ_2^3, λ_3^3\).

9. Find the Eigen values of matrix A=\(\begin{bmatrix}
4 & 1 \\
1 & 4 \\
\end{bmatrix} \).
a) 3, -3
b) -3, -5
c) 3, 5
d) 5, 0
View Answer

Answer: c
Explanation: According to the property of the Eigen value, the eigen values are determined as follows:
4 + 4 = 8
3 + 5 = 8
The sum of the Eigen values is equal to the sum of the principal diagonal elements of the matrix.
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10. Where do we use Eigen values?
a) Fashion or cosmetics
b) Communication systems
c) Operations
d) Natural herbals
View Answer

Answer: b
Explanation: Eigen values are used in communication systems, designing bridges, designing car stereo system, electrical engineering, mechanical companies.

Sanfoundry Global Education & Learning Series – Signals & Systems.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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