# Refrigeration Questions and Answers – Regenerative Air Cooling System

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This set of Refrigeration Multiple Choice Questions & Answers (MCQs) focuses on “Regenerative Air Cooling System”.

1. Regeneration cooling system is a modification of _________
a) simple air cooling system
b) simple evaporative cooling system
c) boot-strap cooling system
d) boot-strap evaporative cooling system

Explanation: Regenerative air cooling system is a modification of simple air cooling system by the addition of a regenerative heat exchanger.

2. Cooling system used for supersonic aircrafts and rockets is?
a) Simple air cooling system
b) Simple evaporative cooling system
c) Boot-strap cooling system
d) Regeneration cooling system

Explanation: Cooling system used for supersonic aircrafts and rockets is of regeneration cooling system type, due to the regenerative heat exchanger and they give lower turbine discharge temperatures than simple air cooling system.

3. Which of the following is not a process in the T-s diagram of the regeneration cooling system?

a) Isentropic ramming
b) Isentropic compression
c) Cooling of air by ram air in the heat exchanger and then cooling of air in regenerative heat exchanger
d) Isothermal expansion

Explanation: T-s diagram of regenerative air cooling system consists of Isentropic ramming, Isentropic compression, Cooling of air by ram air in the heat exchanger and then cooling of air in regenerative heat exchanger, Isentropic compression, isentropic expansion and then heating of air.

4. Simple air cooling system gives maximum cooling effect on ground surface whereas regeneration cooling system has more effect during high speeds.
a) True
b) False

Explanation: Simple air cooling system gives maximum cooling effect on ground surface whereas regeneration cooling system has more effect during high speeds because it gives low turbine discharge temperature than the simple air cooling system.

5. Calculate the power required (P) for maintaining the cabin temperature, when the COP of the regenerative cooling system is given to be 0.25 and the refrigeration load (Q) is 25.
a) 305
b) 350
c) 530
d) 503

Explanation: COP = $$\frac{210×Q}{P×60}$$
0.25 = $$\frac{210×25}{P×60}$$
P = 350 KW.