# Distillation Design Questions and Answers – Minimum Stages

«
»

This set of Distillation Design Multiple Choice Questions & Answers (MCQs) focuses on “Minimum Stages”.

1. The number of theoretical stages, depends on the
a) Stepping off the tray
b) Reflux ratio
c) Operating line
d) Flow rates

Explanation: The number of theoretical stages depends on the reflux ratio R = L0/D, while the reflux ratio itself depends upon the operating line.

2. When R is infinite, the slope of this rectifying becomes
a) 0
b) 1
c) 0.5
d) Can’t be specified

Explanation: When R is infinity, the slope of this line becomes 1, while R is zero the slope of this line reaches infinity.

3. If x=0.4 and y =0.6633 and point xD (0.9, 0.9). Then estimate Rmin
a) 0.9
b) 0.4734
c) 0.4
d) 0.66

Explanation: As Rmin/R+1 = (0.9-0.6633)/ (0.9/0.4) = 0.4734 then 0.4734/1-0.4734 = 0.9.
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

4. If distillate is 95%, and withdrawal is 4 and α=2.5. Estimate total number of tray?
a) 7.7
b) 10
c) 6.7
d) 5.7

Explanation: Using Fenske’s equation and subsuming values we have 2.66/log 2.5= 6.7.

5. For non-ideal cases, to calculate number of stages we use
a) Point efficiency
b) Murphree efficiency
c) Tray efficiency
d) Overall efficiency

Explanation: To calculate the number of stages in a non-ideal case, Murphree efficiency line is used instead of the ideal.

6. Minimum reflux ratio in a distillation column results in
a) Optimum no. of trays
b) Minimum reboiler size
c) Maximum condenser size
d) Minimum number of trays

Explanation: Minimum reflux ratio in a distillation column results in maximum condenser size as inversely proportional.

7. In a tray column, Murphree efficiency
a) Exceed 100%
b) Equal to 100%
c) Can’t be specified
d) Depend upon cases given

Explanation: In a non-ideal case, Murphree efficiency can exceed 100%, also it depends on the cases given and the feed type.

8. For value of m, the change in liquid concentration is independent of tray location if
a) L/V = 1
b) V/L =1
c) L/mV=1
d) Vm/L=1

Explanation: At this condition slope of operating line equals to slope of equilibrium line, i.e. m = 1 this shows the steady state operation.

9. At minimum reflux, No. stages are
a) Unity
b) Infinite
c) Zero
d) Negative

Explanation: Minimum reflux and stages are inversely proportional relation, while at maximum reflux the number of stages are zero.

10. Scaling up from pilot scale to industrial scale only increases
a) Feed rates
b) Reflux ratio
c) No. of stages
d) Composition