# Machine Dynamics Questions and Answers – Isochronous Governor

This set of Machine Dynamics Multiple Choice Questions & Answers (MCQs) focuses on “Isochronous Governor”.

1. When equilibrium speed is constant, then the governor is called ______
a) Pickering
b) Hartung
c) Porter
d) Isochronous

Explanation: Pickering, Porter and Hartung are different categories of governor whereas Isochronous describes the property of the governor by the virtue of which the range in equilibrium speed is zero.

2. For isochronism, range of speed should be equal to mean speed.
a) True
b) False

Explanation: Isochronism describes the property of the governor by the virtue of which the range in equilibrium speed is zero.

3. The sensitiveness of an isochronous governor is ______
a) 0
b) 2
c) 1/2
d) 1

Explanation: For isochronisms N1 – N2 = 0, since this range is 0, the sensitiveness will also be equal to as
sensitiveness = (N1 – N2)÷N.

4. Which of the following type of governor cannot be isochronous?
a) Pickering
b) Porter
c) Hartung
d) Hartnell

Explanation: For a porter governor it is impossible to have the two balls moving at the same speed, thus the range cannot be 0 which makes it impossible to be an isochronous governor.

5. An isochronous governor is not practical because of the following reason.
a) Friction at the sleeve
b) Weight of the spring
c) Impossible to achieve 0 range
d) High use of porter governors

Explanation: The isochronous governor is not of practical use because the sleeve will move to one of its extreme positions immediately the speed deviates from the isochronous speed.
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6. The sensitivity of a governor is 0, and the mean speed is 25 rpm, then it is not possible that the governor will be ________
a) Pickering
b) Porter
c) Hartung
d) Hartnell

Explanation: For a porter governor it is impossible to have the two balls moving at the same speed, thus the range cannot be 0 which makes it impossible to be an isochronous governor. Since sensitiveness is 0, therefore range is 0 hence the governor cannot be porter.

7. For a Hartnell governor which of the following relation regarding r₁/r₂ is true for isochronisms?
a) (M.g + S1) ÷ (M.g + S2)
b) (M.g + S2) ÷ (M.g + S1)
c) S2/ S1
d) S1/ S2

Explanation: For isochronisms the equilibrium speed should remain constant throughout, i.e Range should be 0.
Applying that condition we have r1/r2 = (M.g + S1) ÷ (M.g + S2)

8. Pendulum type governor cannot be isochronous
a) True
b) False

Explanation: For isochronisms, the equilibrium speed should remain constant throughout, i.e Range should be 0 and for pendulum type governors it is impossible to achieve same speed for different balls.

Sanfoundry Global Education & Learning Series – Machine Dynamics.