- #1

- 14

- 0

Hello,

I have been trying to get my head around the concepts of energy, work and momentum. I am trying to build some testing equipment to measure the "transfer of energy" of a moving object striking a pendulum type mass, but am unsure if my physics is correct.

The image attached is my idea for the testing equipment, and below is my working. Now, I am unsure is if I should now take into account rotational physics or the horizontal component.

h = R - x

x = R[tex]\times[/tex] cos a therefore,

h = R - ( R [tex]\times[/tex] cos a)

1/2 [tex]\times[/tex] mv

mgh.

There will be energy losses due to heat, sound, vibration and possibility the rebound of the ball, but does;

mgh roughly = 1/2 [tex]\times[/tex] mv

Am I right in my logic, or do I need to take into account the vertical movement as well?

I wish to place foam pads in front of the mass and look at the height at which the mass is elevated too compared to an impact with no foam pads.

My understanding of the principle of work is that it takes energy to move something in the direction of the force. Even though the force applied is in the vertical, we are still getting horizontal movement.

Can someone share some light on the matter please?

Cheers

K

I have been trying to get my head around the concepts of energy, work and momentum. I am trying to build some testing equipment to measure the "transfer of energy" of a moving object striking a pendulum type mass, but am unsure if my physics is correct.

The image attached is my idea for the testing equipment, and below is my working. Now, I am unsure is if I should now take into account rotational physics or the horizontal component.

**Length h**(maximum height of the mass)h = R - x

x = R[tex]\times[/tex] cos a therefore,

h = R - ( R [tex]\times[/tex] cos a)

**Kinetic Energy of the Ball**1/2 [tex]\times[/tex] mv

^{mv}**Potential Energy of Mass**mgh.

There will be energy losses due to heat, sound, vibration and possibility the rebound of the ball, but does;

mgh roughly = 1/2 [tex]\times[/tex] mv

^{mv}?Am I right in my logic, or do I need to take into account the vertical movement as well?

I wish to place foam pads in front of the mass and look at the height at which the mass is elevated too compared to an impact with no foam pads.

My understanding of the principle of work is that it takes energy to move something in the direction of the force. Even though the force applied is in the vertical, we are still getting horizontal movement.

Can someone share some light on the matter please?

Cheers

K