Farm Machinery Questions and Answers – Plant Protection Equipments – Sprayer’s Classification

This set of Farm Machinery Multiple Choice Questions & Answers (MCQs) focuses on “Plant Protection Equipments – Sprayer’s Classification”.

1. Mysto hand is a type of which sprayer?
a) Stirrup pump type
b) Hand atomiser type
c) Bucket sprayer
d) Boom type field sprayer
View Answer

Answer: b
Explanation: Hand atomiser type sprayers are provided with single action or continuous action air compression pump. When the air is compressed, it is passed over the end of a suction tube which extends down into the spray material. A common type is Mysto hand sprayer and Filt gun.

2. Which sprayer is carried on the back of the operator?
a) Knapsack type
b) Stirrup pump type
c) Rocket sprayer
d) Bucket sprayer
View Answer

Answer: a
Explanation: Knapsack type is a sprayer with the fluid container carried on the back of the operator. It is a compressed air type sprayer which has an air tight chamber. An air pump is mounted on the chamber. The container is filled 3/4th full so as to leave enough space to compress a good volume of air above the spray material.

3. Vane type or Propeller type are which type of pump?
a) Piston pump
b) Centrifugal pump
c) High volume pump
d) Rotary pump
View Answer

Answer: d
Explanation: Rotary pump is commonly used for low pressure sprayers. It may be Vane type or Propeller type. Rollers may be made of nylon, steel or carbon. When the rollers are in operation, they are held against the case by centrifugal force. Rotary pumps are compact and cheap.
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4. What will be the water power which is required to discharge liquid at the rate of 30 litres/min at 30 kg/cm2 pressure?
a) 2.39 KW
b) 9.86 KW
c) 1.47 KW
d) 2.08 KW
View Answer

Answer: c
Explanation: Water power = \(\frac{discharge*head}{1000} \)
Water power = \(\frac{30*9.8}{60}*\frac{30*10}{1000} \) = 1.47 KW

5. Find the suction capacity of a power sprayer if diameter is 25 m, speed is 1100 rev/min length of stroke is 22 mm, number of plunger is 3.
a) 35.61 l/min
b) 23.90 l/min
c) 56.89 l/min
d) 35.47 l/min
View Answer

Answer: a
Explanation: Q = \(\frac{π}{4}\)*D2*L*n*10-6 = \(\frac{π}{4}\)*(25)2*22*1100*10-6 = 11.87 l/min
Total suction capacity = 11.87 * 3
= 35.61 l/min
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6. Hand atomizer is used for spraying in _______
a) orchard
b) field crop
c) nursery
d) forests
View Answer

Answer: c
Explanation: Hand atomiser type sprayers are provided with single action or continuous action air compression pump. When the air is compressed, it is passed over the end of a suction tube which extends down into the spray material. When the compressed air escapes through the nozzle, it carries the spray material along with it. Such sprayers are commonly used for household work, nursery and kitchen gardens.

7. At where is the pressure lower when the chemical travels through the rubber hose?
a) At the discharge part of the power sprayer
b) At the end of the hose
c) At the swirl plate
d) At the spray gun
View Answer

Answer: b
Explanation: When the chemical travels through the rubber hose from the power sprayer, the pressure is lower at the end of the hose than at the discharge part of the power sprayer. Such pressure loss is mainly caused by the friction of the moving chemical against the wall of the hose.
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8. What is pump efficiency?
a) P.E. = Water Horse Power * Shaft Horse Power
b) P.E. = Water Horse Power – Shaft Horse Power
c) P.E. = Water Horse Power + Shaft Horse Power
d) P.E. = \(\frac{Water \, Horse \, Power}{Shaft \, Horse \, Power} \)
View Answer

Answer: d
Explanation: Pump efficiency is defined as the ratio of water horsepower output from the pump to the shaft horsepower input for the pump. Water horsepower is determined by the flow rate and pressure delivered to the pump from the power unit, which is usually an electric motor or internal combustion engine.

9. The distance from the source water surface to the output of the pump is known as _________
a) total head
b) crank handle
c) nozzle
d) flow rate
View Answer

Answer: a
Explanation: Total head is determined by measuring the distance from the source water surface to the output of the pump is producing at the pump outlet. If this value is measured for a centrifugal pump, the distance from the water surface to the pump outlet needs to be measured.
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10. In a pump, suction volume is 25 litres/min and the pump efficiency is 85%. Calculate the shaft power at a pressure of 35kg/cm2
a) 2.65 KW
b) 3.45 KW
c) 1.67 KW
d) 1.10 KW
View Answer

Answer: c
Explanation: Water Power = \(\frac{discharge*head}{1000} = \frac{25*9.8}{60}*\frac{35*10}{1000} \) = 1.42 KW
Shaft Power = \(\frac{1.42}{0.85} \) = 1.67 KW

Sanfoundry Global Education & Learning Series – Farm Machinery.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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