Farm Machinery Questions and Answers – Disc Plough

This set of Farm Machinery Multiple Choice Questions & Answers (MCQs) focuses on “Disc Plough”.

1. Which plough is used is used to break Hard pan or plough sole layer of soil?
a) Subsoiler
b) Chisel plough
c) Rotavator
d) Rotating auger plough
View Answer

Answer: b
Explanation: Chisel plough is a plough used to cut through hard soils by means of a number of narrow tynes. It is useful for breaking hard layers of soil just below the regular ploughing depth.

2. How is effect of speed on draft expressed?
a) Ds = D0 + KS2
b) Ds = D0 – KS2
c) Ds = D0 * KS2
d) Ds = D0 / KS2
View Answer

Answer: a
Explanation: Draft increases with increase in speed in most of the tillage implements. This may be due to rapid acceleration of any soil that is moved appreciably.

3. In order to provide furrows at all times on the right-hand side of the plough which method/methods is/are used?
a) Gathering
b) Casting
c) Gathering and casting
d) None of the above
View Answer

Answer: c
Explanation: Whenever a plough works round a strip of ploughed land, it is said to be gathering, whereas whenever a plough works round a strip of unploughed land, it is said to be casting.

4. What is the depreciated value after n years using declining balance method?
a) D = P(1-r)n
b) D = P(1/r)n
c) D = P(1*r)n
d) D = P(1+r)n
View Answer

Answer: a
Explanation: In this method, a uniform rate is used for each year to the remaining values, including salvage value of the machine. Depreciation amount is different for each year, during machine life.

5. What is the Break Even Point?
a) Uc = \(\frac{Fc}{x}\)*Ox
b) Uc = \(\frac{Fc}{x}\)+Ox
c) Uc = \(\frac{Fc}{x}\)-Ox
d) Uc = Fc*x*Ox
View Answer

Answer: b
Explanation: When a common variable affects the cost of two methods, the value of variables at which the cost of use for both the method will be equal. This value of variable is known as break-even point. At break-even point unit cost of operation of big and small machine will be same.
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6. What is the formula for computing depreciation in straight line method?
a) D = \(\frac{P-S}{L*H} \)
b) D = \(\frac{P+S}{L*H} \)
c) D = \(\frac{P-S}{L+H} \)
d) D = (P-S)*(L*H)
View Answer

Answer: a
Explanation: Depreciation is the decrease in cost of machines with passage of time, whether it is used or not. Simple line method is commonly used for determining the depreciation of agricultural machines.

7. What are the ways of doing round and round ploughing?
a) Starting at the outer end
b) Starting at the centre
c) Back furrowing
d) Starting at the outer end & starting at the centre
View Answer

Answer: d
Explanation: In starting at the centre method a small plot of land is marked in the middle of the field and it is ploughed first. After that, the plough works round this small plot and the entire plot is completed. In starting at the outer end tractor starts ploughing at one end of the field and then moves on all sides of the plot and comes gradually from the sides to the centre of the field.

8. What is distance of centre of resistance from share wing?
a) 3/4th size of plough
b) 3/4th size of share
c) 3/4th size of tractor
d) 3/4th size of frog
View Answer

Answer: a
Explanation: Centre of resistance is the point at which the resultant of all the horizontals and vertical force acts. The centre lies at a distance equal to 3/4th size of plough from the share wing.

Sanfoundry Global Education & Learning Series – Farm Machinery.


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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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