Tabulation Questions and Answers – Set 3

This set of Data Interpretation Questions and Answers (MCQs) focuses on “Tabulation – Set 3”.

1. Study the table and find the average height of all the boys.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130

a) 150.5
b) 151
c) 151.5
d) 152
View Answer

Answer: b
Explanation: The average height of all the boys = (153 + 158 + 147 + 145 + 156 + 146 + 157 + 146) / 8 = 151

2. Study the table and find the average height of first 4 boys.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130
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a) 150
b) 150.75
c) 151
d) 151.75
View Answer

Answer: b
Explanation: The average height of the first 4 boys = (153 + 158 + 147 + 145) / 4 = 150.75

3. Study the table and find the average height of the last 4 boys.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130

a) 151
b) 151.25
c) 152
d) 152.25
View Answer

Answer: b
Explanation: The average height of the last 4 boys = (156 + 146 + 157 + 146) / 4 = 151.25

4. Study the table and find the average height of all the girls.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130
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a) 140
b) 140.25
c) 140.50
d) 140.75
View Answer

Answer: b
Explanation: The average height of all the girls = (134 + 146 + 149 + 137 + 142 + 143 + 141 + 130) / 8 = 140.25

5. Study the table and find the average height of first 5 girls.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130
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a) 141.2
b) 141.4
c) 141.6
d) 141.8
View Answer

Answer: c
Explanation: The average height of the first 5 girls = (134 + 146 + 149 + 137 + 142) / 5 = 141.6

6. Study the table and find the average height of the last 7 girls.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130

a) 144.41
b) 144.14
c) 141.41
d) 141.14
View Answer

Answer: d
Explanation: The average height of the last 7 girls = (146 + 149 + 137 + 142 + 143 + 141 + 130) / 7 = 141.14

7. Study the table and find the average height of all the boys and girls.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130

a) 145.635
b) 145.625
c) 145.250
d) 145.5
View Answer

Answer: b
Explanation: The average height of the boys and girls combined = (140.25 + 151) / 2 = 145.625

8. Study the table and find the average height of boy 6 and girl 4.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130

a) 151.5
b) 141.5
c) 131.5
d) 145.5
View Answer

Answer: b
Explanation: the average height of boy 6 and girl 4 = (146 + 137) / 2 = 141.5

9. Study the table and find the average height of boy 5, 6, 7 and girl 3, 7, 8.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130

a) 141.5
b) 146.5
c) 151.5
d) 152.5
View Answer

Answer: b
Explanation: The average height of boy 5, 6, 7 and girl 3, 7, 8 = (156 + 146 + 157 + 149 + 141 + 130) / 6 = 146.5

10. Study the table and find the average height of all the boys and first 5 girls.

Heights 1 2 3 4 5 6 7 8
Boys 153 158 147 145 156 146 157 146
Girls 134 146 149 137 142 143 141 130

a) 141.1
b) 143.6
c) 146.3
d) 149.2
View Answer

Answer: c
Explanation: The average height of all the boys and first 5 girls = (151 + 141.6) / 2 = 146.3

11. Study the table and find the average height of all the results.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 144.22 units
b) 150.5 units
c) 162.22 units
d) 167.5 units
View Answer

Answer: a
Explanation: The average height of all the results = (143 + 141 + 145 + 142 + 147 + 149 + 152 + 139 + 140) / 9 = 144.22 units

12. A’s weight is what percentage of the total weight of the results?

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 10%
b) 10.3%
c) 11%
d) 11.3%
View Answer

Answer: b
Explanation: The total weight = 66 + 67 + 76 + 78 + 68 + 86 + 57 + 75 + 67 = 640 units
A’s weight = 66 units
The required percentage = 66 / 640 * 100 = 10.31% ≈ 10.3 %

13. Study the table and find the average age of all the results.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 32 units
b) 32.33 units
c) 33 units
d) 33.33 units
View Answer

Answer: b
Explanation: The average age of all the results = (20 + 25 + 43 + 34 + 23 + 25 + 27 + 36 + 33) / 8 = 266 / 8 = 32.33 units

14. Study the table and find the percentage of b’s weight in the total weight.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 10%
b) 10.5%
c) 11%
d) 11.5%
View Answer

Answer: b
Explanation: The total weight = 66 + 67 + 76 + 78 + 68 + 86 + 57 + 75 + 67 = 640 units
B’s weight = 67 units
The required percentage = 67 / 640 * 100 = 10.46% ≈ 10.5%

15. Study the table and find what is the percentage share of a’s age in the total age of the results?

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 5.5%
b) 6.5%
c) 7.5%
d) 8.5%
View Answer

Answer: c
Explanation: The total age of the results = 20 + 25 + 43 + 34 + 23 + 25 + 27 + 36 + 33 = 268 units
A’s age = 20 units
The required result = 20 / 268 * 100 = 7.46% ≈ 7.5%

16. Study the table and find the average age of the first 5 results.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 27 units
b) 28 units
c) 29 units
d) 30 units
View Answer

Answer: c
Explanation: The required average = (20 + 25 + 43 + 34 + 23) / 5 = 145 / 5 = 29 units

17. If the age of a, b and c is doubled, Study the table, and find the new average age.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 36.55 units
b) 37.55 units
c) 38.55 units
d) 39.55 units
View Answer

Answer: c
Explanation: The previous total = 20 + 25 + 43 + 34 + 23 + 25 + 27 + 36 + 33 = 268 units
The new total = 268 + 20 + 25 + 34 = 347
The new average = 347 / 9 = 38.55 units

18. Study the table and find the percentage contribution of c’s age in the total weight.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 12.66%
b) 12.68%
c) 12.7%
d) 12.75%
View Answer

Answer: b
Explanation: The total age = 20 + 25 + 43 + 34 + 23 + 25 + 27 + 36 + 33 = 268 units
C’s age = 34 units
The required percentage = 34 / 268 * 100 = 12.68%

19. Study the table and find the percentage contribution of I’s age in the total weight.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 12.3%
b) 11.4%
c) 10.5%
d) 9.8%
View Answer

Answer: a
Explanation: The total age = 20 + 25 + 43 + 34 + 23 + 25 + 27 + 36 + 33 = 268 units
I’s age = 33 units
The required percentage = 33 / 268 * 100 = 12.31% ≈ 12.3%

20. Study the table and find what is the percentage contribution of g’s weight in the total weight of the results.

A B C D E F G H I
Age 20 25 34 43 23 25 27 36 33
Weight 66 67 76 78 68 86 57 75 67
Height 143 141 145 142 147 149 152 139 140

a) 8.8%
b) 8.9%
c) 9.8%
d) 9.9%
View Answer

Answer: b
Explanation: The total weight of the results = 66 + 67 + 76 + 78 + 68 + 86 + 57 + 75 + 67 = 640 units
G’s weight = 57 units
The required percentage = 57 / 640 * 100 = 8.9%

To practice all aptitude questions, please visit “Data Interpretation Questions”, “1000+ Quantitative Aptitude Questions”, and “1000+ Logical Reasoning Questions”.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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