This set of Waste Water Engineering Objective Questions & Answers focuses on “Advanced Oxidation Process-H2O2/UV”.
1. Advanced oxidation processes are used to remove inorganic materials in water and wastewater.
a) True
b) False
View Answer
Explanation: Advanced oxidation processes in a broad sense, are a set of chemical treatment procedures designed to remove organic materials in water and wastewater by oxidation through reactions with hydroxyl radicals.
2. Organic materials in wastewater are removed by oxidation through reactions with _______
a) hydrogen
b) hydroxyl radicals
c) water
d) oxygen
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Explanation: Advanced oxidation processes, in a broad sense, are a set of chemical treatment procedures designed to remove organic (and sometimes inorganic) materials in water and wastewater by oxidation through reactions with hydroxyl radicals.
3. What is the process used in AOP?
a) Oxidation
b) Reduction
c) Substitution
d) Chlorination
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Explanation: The term AOP usually refers more specifically to a subset of such chemical processes that employ ozone (O3), hydrogen peroxide (H2O2) and/or UV light. One such type of process is called in situ chemical oxidation.
4. Advanced oxidation processes are cheap.
a) True
b) False
View Answer
Explanation: The cost of advanced oxidation processes are usually high since there is a continuous input of expensive chemical reagents that are required for the operation.
5. The cost of AOP is high because of _________
a) High pumping cost
b) Continuous input of energy
c) Expensive chemical reagents
d) UV radiations
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Explanation: The cost of advanced oxidation processes are usually high since there is a continuous input of expensive chemical reagents that are required for the operation. The system requires hydroxyl radicals and other reagents proportional to the number of contaminants to be removed.
6. What is the oxidative potential of hydroxyl radical?
a) 2.08
b) 2.18
c) 2.28
d) 1.78
View Answer
Explanation: The oxidative potential of hydroxyl radical is 2.28 V, the oxidation potential of ozone is 2.07 V and the oxidation potential of hydrogen peroxide is 1.78 V.
7. What is the EE/O for 1,4 dioxane in kWh/1000 US gal/order?
a) 2-6
b) 30
c) 15
d) 15-20
View Answer
Explanation: the EE/O for 1,4 dioxane in kWh/1000 US gal/order is 2-6. With the EE/O value, the UV dosage can be calculated. With the UV dosage required, the cost of electricity can be calculated.
8. What is the EE/O for atrazine in kWh/1000 US gal/order?
a) 2-6
b) 30
c) 20
d) 15-20
View Answer
Explanation: The EE/O for atrazine in kWh/1000 US gal/order is 30. This is used in calculating the UV dosage required to oxidize atrazine. The EE/O value differs from one organic compound to the other.
9. What is the EE/O for benzene in kWh/1000 US gal/order?
a) 2-5
b) 5-7
c) 7-9
d) 9-11
View Answer
Explanation: The EE/O for benzene in kWh/1000 US gal/order is 2-5. The EE/O for chlorobenzene in kWh/1000 US gal/order is 5. Benzene and chlorobenzene are aromatic compounds.
10. What is the EE/O for DCA in kWh/1000 US gal/order?
a) 5
b) 15
c) 20
d) 25
View Answer
Explanation: The EE/O for DCA in kWh/1000 US gal/order is 15. DCA is dichloro acetic acid. This requires a reduction catalyst prior to the UV dosage.
11. What is the EE/O for chloroform in kWh/1000 US gal/order?
a) 5-10
b) 15
c) 20-25
d) 25-30
View Answer
Explanation: The EE/O for chloroform in kWh/1000 US gal/order is 15. Chloroform is also called as trichloromethane. This requires a reduction catalyst prior to the UV dosage.
12. How is UV dosage expressed mathematically?
a) UV dosage = EE/O log(Ci)/(Cf)
b) UV dosage = EE/O /log(Ci)/(Cf)
c) UV dosage = log(Ci)/(Cf)
d) UV dosage = EE/O (Ci)/(Cf)
View Answer
Explanation: UV dosage = EE/O log(Ci)/(Cf). Where Ci is the initial concentration. Cf is the final concentration.
13. How is the operating cost calculated for an advanced oxidation process system in $ per 1000US gallon?
a) Total operating cost = 1.45 x electrical cost + Peroxide cost
b) Total operating cost = 0.45 x electrical cost + Peroxide cost
c) Total operating cost = electrical cost + Peroxide cost
d) Total operating cost = 1.5 x electrical cost + Peroxide cost
View Answer
Explanation: Total operating cost = 1.45 x electrical cost + Peroxide cost. This cost would be in $ per 1000US gallon. The cost of hydrogen peroxide is hydrogen peroxide concentration in ppm x ($ 0.005 / ppm/1000 US gallon).
14. How is the UV power calculated?
a) UV power = [UV dosage x 60 x flow(US gallons)]/1000
b) UV power = [UV dosage x 600 x flow(US gallons)]/1000
c) UV power = [UV dosage x flow(US gallons)]/1000
d) UV power = [UV dosage x 16 x flow(US gallons)]/1000
View Answer
Explanation: UV power = [UV dosage x 60 x flow(US gallons)]/1000. Once the UV power is known capital cost can be calculated. The UV power varies proportionally with the flow.
15. What is the EE/O for Vinyl chloride in kWh/1000 US gal/order?
a) 1-2
b) 2-3
c) 3-5
d) 5-7
View Answer
Explanation: The EE/O for Vinyl chloride in kWh/1000 US gal/order is 2-3. This is an organic chloride. It is used to produce poly vinyl chloride.
16. What is the EE/O for Xylene in kWh/1000 US gal/order?
a) 2-5
b) 5-7
c) 7-9
d) 9-12
View Answer
Explanation: The EE/O for Xylene in kWh/1000 US gal/order is 2-5. This is also known as dimethyl benzene. This is also called as xylol.
17. What is the EE/O for TCA in kWh/1000 US gal/order?
a) 15
b) 20
c) 10
d) 30
View Answer
Explanation: The EE/O for TCA in kWh/1000 US gal/order is 15. This is also called tricarboxylic acid. This requires a reduction catalyst prior to the UV dosage.
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