C++ Program to Solve Tower of Hanoi using Binary Value

This C++ program displays the solution to the Tower of Hanoi problem using the base-2 representation of the move number with the following rules:-
There is one binary digit (bit) for each disk.
The most significant (leftmost) bit represents the largest disk. A value of 0 indicates that the largest disk is on the initial peg, while a 1 indicates that it’s on the final peg.
The bitstring is read from left to right, and each bit can be used to determine the location of the corresponding disk.
A bit with the same value as the previous one means that the corresponding disk is stacked on top the previous disk on the same peg.
A bit with a different value to the previous one means that the corresponding disk is one position to the left or right of the previous one.

Here is the source code of the C++ program to display the movement of disks from one peg to the other. This C++ program is successfully compiled and run on DevCpp, a C++ compiler. The program output is given below.

```
/*
```

 * C++ program to Solve Tower of Hanoi Problem using Binary Value

```
 */
```
```
#include<stdio.h> 
```
```
#include<conio.h>
```
```
#include<iostream>
```
```
using namespace std;
```
```
int main()
```
```
{
```
```
    int n, x;
```
```
    cout<<"\nEnter the No. of Disks: ";
```
```
    cin>>n;
```
```
    for (x = 1; x < (1 << n); x++)
```
```
    {
```

        printf("\nMove from Peg %i to Peg %i", (x&x-1)%3+1, ((x|x-1)+1)%3+1);

```
    }
```
```
    cout<<"\n";
```
```
    getch();
```
```
}
```

Output
Enter the No. of Disks: 4
 
Move from Peg 1 to Peg 3
Move from Peg 1 to Peg 2
Move from Peg 3 to Peg 2
Move from Peg 1 to Peg 3
Move from Peg 2 to Peg 1
Move from Peg 2 to Peg 3
Move from Peg 1 to Peg 3
Move from Peg 1 to Peg 2
Move from Peg 3 to Peg 2
Move from Peg 3 to Peg 1
Move from Peg 2 to Peg 1
Move from Peg 3 to Peg 2
Move from Peg 1 to Peg 3
Move from Peg 1 to Peg 2
Move from Peg 3 to Peg 2

Sanfoundry Global Education & Learning Series – 1000 C++ Programs.

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