1. In the shell, by default, all variables are considered and stored as
a) string
b) integer
c) character
d) float
View Answer
Explanation: None.
2. Which command reads user input from the terminal and assign this value to a variable name?
a) read
b) get
c) declare
d) set
View Answer
Explanation: None.
3. Which one of the following statement is true about variables in shell?
a) variables do not require declaration before assigning value to them
b) variables are case sensitive
c) to extract the contents of a variable, we have to provide the variable a preceding $
d) all of the mentioned
View Answer
Explanation: None.
4. Which one of the following is not a valid shell variable?
a) _san
b) san_2
c) _san_2
d) 2_san
View Answer
Explanation: The shell variable can contain only letters(a to z or A to Z), numbers(0 to 9), or a underscore character(_) and a variable can not start with a number.
5. To redefine a variable, it can be removed from the list of variables by using the command
a) unset
b) delete
c) remove
d) clear
View Answer
Explanation: None.
6. What is the output of this program?
#!/bin/bashsan_var="Sanfoundry"
echo "$san_var"
echo '$san_var'
echo '"$san_var"'
echo "'$san_var'"
echo \$san_var
exit 0
a) Sanfoundry
$san_var
“$san_var”
‘Sanfoundry’
$san_var
b) Sanfoundry
Sanfoundry
“Sanfoundry”
‘Sanfoundry’
Sanfoundry
c) program will generate an error message
d) program will print nothing
View Answer
Explanation: Using double quotes does not affect the substitution of the variable, while single quotes and backslash do.
Output:
[email protected]:/home/sanfoundry# ./test.sh
Sanfoundry
$san_var
“$san_var”
‘Sanfoundry’
$san_var
[email protected]:/home/sanfoundry#
7. What is the output of this program?
#!/bin/bashvar1=10
$var1=20
echo $var1
exit 0
a) program will print 10
b) program will generate a warning message
c) program will print 20
d) program will print 10 & 20
View Answer
Explanation: The doller sign ($) is used to access a variable’s value, not to define it.
Output:
[email protected]:/home/sanfoundry# ./test.sh
./test.sh: line 3: 10=20: command not found
10
[email protected]:/home/sanfoundry#
8. What is the output of this program?
#!/bin/bashvar[1]=san_1
var[2]=san_2
var[3]=san_3
echo ${var[*]}
exit 0
a) san_1
b) san_2
c) san_3
d) san_1 san_2 san_3
View Answer
Explanation: All items of an array can be accessed by using ${[*]} or ${[@]}.
Output:
[email protected]:/home/sanfoundry# ./test.sh
san_1 san_2 san_3
[email protected]:/home/sanfoundry#
9. What is the output of this program?
#!/bin/bashsan_var=helloreadonly san_varsan_var=hiecho $san_var
exit 0
a) hello
b) hi
c) nothing will print
d) none of the mentioned
View Answer
Explanation: After the execution of the ‘readonly’ command, shell will not provide the permission to overwrite the value stored in variable ‘san_var’.
Output:
[email protected]:/home/sanfoundry# ./test.sh
./test.sh: line 4: san_var: readonly variable
hello
[email protected]:/home/sanfoundry#
10. What is the output of this program?
#!/bin/bashsan_var=10
echo "the value of \"san_var\" is $san_var"
exit 0
a) the value of “san_var” is 10
b) the value of is 10
c) the value of san_var is $san_var
d) the value of “san_var” is $san_var
View Answer
Explanation: None.
Output:
[email protected]:/home/sanfoundry# ./test.sh
the value of “san_var” is 10
[email protected]:/home/sanfoundry#
Sanfoundry Global Education & Learning Series – Linux Administration & Programming.
Here’s the list of Best Reference Books in Linux Commands & Shell Programming.
Here’s the list of Best Reference Books in Linux Kernel, Device-Drivers & System Programming.
To practice all questions on Linux Administration & Programming, here is complete set of 1000+ Multiple Choice Questions and Answers on Linux.
