Probability Distributions Questions and Answers – Set 3

This set of Probability Multiple Choice Questions & Answers (MCQs) focuses on “Probability Distributions – Set 3”.

1. For which of the following conditions does the Geometric Random Variable P[X=n] = (1-p)n-1p, hold?
a) Independent trials and n=0, 1, 2, 3, …
b) Independent trials and n=1, 2, 3, …
c) Dependent trials and n=0, 1, 2, 3, …
d) Dependent trials and n=1, 2, 3, …
View Answer

Answer: b
Explanation: The Geometric random variable always holds for independent trials and not dependent trials. It should also not start with 0. Hence the condition will hold for n=1, 2, 3 …

2. F(x) = (1/2)e-|x|, -∞<x<∞, is a possible probability density function.
a) True
b) False
View Answer

Answer: a
Explanation: |x| is an even function;
|x|=x for all x≥0;
so, \(\int_{-∞}^{∞}f(x)dx=\int_{-∞}^{∞}e^{-|x|} dx = \int_{0}^{∞}e^{-x} dx=1,f(x)≥0,∀x\).

3. The set of points of discontinuity of a distribution function is __________
a) at least nonenumerable
b) at most nonenumerable
c) at least enumerable
d) at most enumerable
View Answer

Answer: d
Explanation: Any discontinuity in the distribution function can be mapped to a disjoint interval. The length of the interval is bound and hence countable. Thus the discontinuities are also countable i.e. enumerable.
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4. The curve y=f(x) is called the distribution curve of the corresponding random variable x. It is evident that the distribution curve lies between ____________
a) Y=0, X=0
b) Y=0, X=1
c) Y=0, Y=1
d) X=0, X=1
View Answer

Answer: c
Explanation: Y is the distribution curve. Hence, it displays the probability of finding a certain point X. Therefore, Y can take any value between 0 and 1. Thus the curve lies between y=0 and y=1.

5. The number of changes of a stochastic process in a given interval of time follows _____________ law under certain conditions.
a) binomial
b) poisson
c) gamma
d) beta
View Answer

Answer: b
Explanation: The stochastic process can be represented as a counting process that displays a random number of points or events that have occurred until a particular time. The number of changes in the given interval is a Poisson variable dependent on time and another parameter.
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6. The following is a probability mass function.
F(x)=\(\begin{Bmatrix}2 \,for \,x=\frac{1}{2}\\1 \,for \,x=\frac{1}{4}\\-1 \,for \,x=\frac{3}{4}\\0,elsewhere \end{Bmatrix}\)
a) True
b) False
View Answer

Answer: b
Explanation: f(\(\frac{3}{4}\)) = -1 < 0;
A probability function has to take values between 0 and 1 i.e. it can never be -1. Thus, f(x) is not a probability mass function.

7. For a two dimensional distribution function F(x, y), F(x, y) is ____________ for both the variable x and y.
a) monotonically decreasing
b) monotonically non-decreasing
c) monotonically increasing
d) monotonically non-increasing.
View Answer

Answer: b
Explanation: Let F(x, y), be denoted as a. Now, suppose a is positive. Then the 2-D function F(x, y), F(x, y) is also positive. Now, if a is negative, then a*a has to be positive. Thus again, F(x, y), F(x, y) is positive irrespective of the variables and the function.
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8. The random variable is uniformly distributed in (0, 1). Then the probability distribution of Y = -2 logeX is ____________
a) Fy(y)=\(\frac{1}{2} e^{\frac{-1}{2} y}\), 0<y<∞
b) Fy(y)=\(\frac{1}{2} e^{\frac{1}{2} y}\), 0<y<∞
c) Fx(y)=\(\frac{1}{2} e^{\frac{-1}{2} y}\), 0<y<∞
d) Fy(y)=\(\frac{1}{2} e^{\frac{-1}{2}}\), 0<y<∞
View Answer

Answer: a
Explanation: Differentiating Y = -2 logeX, we get \(\frac{dy}{dx}=\frac{-2}{x}\). Now, \(\frac{dy}{dx}=\frac{-2}{x}\) <0 ∀x∈(0,1)
Hence, Fy(y) = Fx(x)\(|\frac{dy}{dx}|\) i.e. Fy(y)=\(\frac{1}{2} e^{{-1}{2} y}\),0<y<∞

9. The salary of workers in a factory follows a binomial (300, 1/6) distribution. What will be the mean and standard deviation of the distribution curve?
a) 40, 41.6
b) 40, 6.4
c) 50, 41.6
d) 50, 6.4
View Answer

Answer: d
Explanation: For a binomial (n, p) distribution, the mean is (n*p) and the standard deviation is the square root of (n*p*(1-p)).
Now, n = 300, p = 1/6, 1-p = 5/6
Mean = (n*p) = 300 * 1/6 = 50
SD = square root of (50 * 5/6) = 6.4.
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10. The graph of the standard normal distribution curve is?
a)
machine-learning-questions-answers-distributions-q10a
b)
machine-learning-questions-answers-distributions-q10b
c)
machine-learning-questions-answers-distributions-q10c
d)
machine-learning-questions-answers-distributions-q10d
View Answer

Answer: b
Explanation: For every standard normal distribution curve, the standard deviation has to be 1 and the mean or the average of points has to be zero. Thus, the curve must pass through the y-axis in the middle of the curve. Only curve (b) passes through the y-axis in the middle of the curve.

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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