# Basic Electronics Engineering Questions and Answers – Transducers – Resistance Thermometer and Hall Effect

This set of Basic Electronics Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Transducers – Resistance Thermometer and Hall Effect”.

1. The resistance of the most electrical conductors varies with ________
a) Pressure
b) Temperature
c) Velocity
d) Speed

Explanation: The resistance of the electrical conductors varies with temperature. The change in temperature lead to increase or decrease in the area of the conductor because the conductor is made up of metals and the metals elongate when temperature is increased leading to change in resistance.

2. The resistance of the electrical conductors varies according to the relation _________
a) R=R0(1-α.T+β.T2+….)
b) R=R0(1+α.T+β.T2+….)
c) R=R0(1+α/T+β/T2+….)
d) R=R0(1-α/T+β/T2+….)

Explanation: The resistance of the electrical conduction varies according to the relation R=R0(1+α.T+β.T2+….) where, R=resistance at T, R0=resistance at temperature T0, α,β= constants, T= rise in temperature above T0.

3. If there is very small range of temperature T, then the change in resistance of the conductor will have the relation as _________
a) R=R0(1+α.T)
b) R=R0(1+α)
c) R=R0(1+α/T)
d) R=R0(1-α/T)

Explanation: If there is very small range of temperature T, then the change in resistance of the conductor will have the relation as R=R0(1+α.T). Actually, the relation is R=R0(1+α.T+β.T2+….) then here the value of T is small so all the other powers of T are neglected as they are too small.

4. The one of the important properties of the materials used for resistance thermometers are high temperature coefficient of resistance.
a) True
b) False

Explanation: The one of the important properties of the materials used for resistance thermometers are high temperature coefficients of resistance, stable properties of resistance and a high resistivity to permit.

5. Tungsten has a suitable temperature coefficient resistance but it is hard to form and _____
a) Soft
b) Brittle
c) Crystalline
d) Complex

Explanation: Tungsten has a suitable temperature coefficient resistance but it is hard to form and brittle in nature where as the copper has very low resistivity that is why it is widely used as conductor.

6. The temperature coefficient is linear over a large range of temperature for ______
a) Platinum
b) Nickel
c) Copper
d) Tungsten

Explanation: The temperature coefficient is linear over a large range of temperature for platinum. This is the main advantage of the platinum over the nickel. Copper and tungsten are also not having this efficiency.

7. Nickel is used largely as it is easy to obtain the __________
a) Linear temperature
b) Impure state
c) Pure state
d) Viscosity

Explanation: Nickel is used largely as it is easy to obtain the pure state of the metal and for platinum also it is easy to obtain the pure state. Platinum has the other advantage than nickel is having linear temperature coefficient over large range of temperature.

8. Which of the following is one of the parts of the resistance thermometer?
a) Sheath
b) Force rod
c) Welding joints
d) Cross spring

Explanation: Sheath is the part of the resistance thermometer and the force rod, welding joints and cross spring are the parts of the parts of the strain gauge. The other parts of the resistance thermometer are mounting threads, lead support,element, connecting wires etc.

9. The calendar equation determines the relationship between the _________for platinum elements.
a) Resistance- temperature
b) Resistance- velocity
c) Velocity- temperature
d) Velocity-distance

Explanation: The calendar equation is used know the relationship between the resistance and temperature. This only applicable for the platinum elements generally.

10. The calendar equation is given by _______
a) T={100(RT + R0)/(R100 -R0)}+d(T/100 – 1)T/100
b) T={100(RT – R0)/(R100 +R0)}+d(T/100 – 1)T/100
c) T={100(RT – R0)/(R100 -R0)}+d(T/100 – 1)T/100
d) T={100(RT + R0)/(R100 +R0)}+d(T/100 – 1)T/100

Explanation: The calendar equation determines the relation between the resistance and temperature and it is mainly applicable for the platinum resistance elements. The equation is T={100(RT – R0)/(R100 – R0)}+d(T/100 – 1)T/100, where R0, RT,R100 is resistance at temperature T and 0°C 100°C respectively.

Sanfoundry Global Education & Learning Series – Basic Electronics Engineering.

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