Java Program to Perform Partition of an Integer in All Possible Ways

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This is a java program to perform partition of an integer in all possible ways. Every partition when added should result in the given integer.

Here is the source code of the Java Program to Perform Partition of an Integer in All Possible Ways. The Java program is successfully compiled and run on a Windows system. The program output is also shown below.

  1. //This is sample program to print a unique partitions of a given number
  2. import java.util.Scanner;
  3.  
  4. public class Unique_Partitions_Number 
  5. {
  6.     public static void print(int[]p, int n)
  7.     {
  8.         for(int i=0; i<n; i++)
  9.             System.out.print(p[i]+" ");
  10.         System.out.println();
  11.     }
  12.     public static void generateUniquePartition(int n)
  13.     {
  14.         int []p = new int[n+n];
  15.         int k = 0;
  16.         p[k] = n;
  17.         while(true)
  18.         {
  19.             print(p, k=1);
  20.             int rem_value = 0;
  21.             while(k >= 0 && p[k] == 1)
  22.             {
  23.                 rem_value += p[k];
  24.                 k--;
  25.             }
  26.             if(k < 0)
  27.                 return;
  28.  
  29.             p[k]--;
  30.             rem_value++;
  31.  
  32.             while(rem_value > p[k])
  33.             {
  34.                 p[k+1] = p[k];
  35.                 rem_value -= p[k];
  36.                 k++;
  37.             }
  38.             p[k+1] = rem_value;
  39.             k++;
  40.         }
  41.     }
  42.     public static void main(String args[])
  43.     {
  44.         System.out.println("Unique Partitioning of a given number");
  45.         System.out.println("Enter the number:");
  46.         Scanner sc = new Scanner(System.in);
  47.         int n = sc.nextInt();
  48.         generateUniquePartition(n);
  49.         sc.close();
  50.     }
  51. }

Output:

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$ javac Unique_Partitions_Number.java
$ java Unique_Partitions_Number
Unique Partitioning of a given number
Enter the number:
4
 
4 
3 1
2 2
2 1 1
1 1 1 1

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