This is a C++ Program to Convert a Given Binary Number to its Decimal Equivalent.
The program converts a binary number to its decimal equivalent.
1. The program takes a binary number.
2. Using a while loop, the remainders of the number are multiplied with powers of 2.
3. The decimal equivalent that is the result is printed.
4. Exit.
Here is the source code of C++ Program to Convert a Given Binary Number to its Decimal Equivalent. The program output is shown below.
#include<iostream>using namespace std;
int main ()
{int num, rem, temp, dec = 0, b = 1;
cout << "Enter the binary number : ";
cin >> num;
temp = num;
while (num > 0)
{rem = temp % 10;
dec = dec + rem * b;
b *= 2;
temp /= 10;
}cout << "The decimal equivalent of " << num << " is " << dec;
return 0;
}
1. The user is asked to enter a binary number and it is stored in the variable ‘num’.
2. The variable ‘b’ is initialized as 1 and ‘dec’ as 0. num is copied to the variable ‘temp’.
3. Using a while loop, modulus of temp is stored in ‘rem’.
4. rem is multiplied with b and added to dec.
5. In every iteration, b is multiplied with 2.
6. The loop continues till temp is less than 0.
7. The decimal equivalent is stored in dec and printed.
Case 1 : Enter the binary number : 10 The decimal equivalent of 10 is 2 Case 2 : Enter the binary number : 01010101 The decimal equivalent of 1010101 is 85 Case 3 : Enter the binary number : 1111 The decimal equivalent of 1111 is 15
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